In: Statistics and Probability
Solution :
Given that,
= 690.24
= 58.36.
n = 25
A ) The standard error = (/n)
= (58.36./ 25 )
= 11.67
The standard error = 11.67
B ) At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z/2* (/n)
= 1.960 * (58.36./ 25 )
= 22.88
Margin of error = E = 22.80
At 95% confidence interval estimate of the population mean is,
- E < < + E
690.24 - 22.88 < < 690.24 + 22.88
667.36 < < 713.12
C ) The upper bounds = 713.12
The lower bounds = 667.36