In: Operations Management
Given the following information set up the problem in a transportation table and solve for the minimum-cost plan:
PERIOD | ||||
1 | 2 | 3 | ||
Demand | 550 | 700 | 750 | |
Capacity | ||||
Regular | 500 | 500 | 440 | |
Overtime | 50 | 50 | 50 | |
Subcontract | 120 | 120 | 100 | |
Beginning inventory | 100 | |||
Costs | ||||
Regular time | $ | 60 per unit | ||
Overtime | $ | 80 per unit | ||
Subcontract | $ | 90 per unit | ||
Inventory carrying cost | $ | 1 per unit per month | ||
Back-order cost | $ | 3 per unit per month | ||
Suppose that an inventory carrying cost is increased $2 per unit
per period. What will the additional cost of the optimal plan be?
(Omit the "$" sign in your response.)
Additional cost
$
I've asked this question a couple of times and it has been incorrect. So.. the answer is not 440 haha.. good luck! Thanks for your help!
The transportation model for aggregate plan is as follows:
(the net demand in month 1 = 550 – 100 (inventory) = 450 units
The optimal Solution is as follows:
In month 1,
Regular production = 500 (340 units in month 1 and store 160 units to satisfy month 3 demand)
OT = 50 (30 in month 1 and store 20 units to satisfy month 2 demand)
Subcontract = 90 for month 1
In month 2,
Regular production = 500 (500 units in month 2)
OT = 50 in month 2)
Subcontract = 120 for month 2
In month 3,
Regular production = 440 units in month 3)
OT = 50 in month 3
Subcontract = 100 for month 3
Total optimal cost = $126,650
If the inventory cost is increased by $2 per unit, the optimal solution remain same, but the inventory holding cost will increase.
Additional cost = 160 units x 2 months x ($2 - $1) + 30 units x 1 month x ($2 - $1) = $350
Additional Cost = $350