2Cu2+ + 4KI → 2CuI + I2 + 4K+ (rxn 1) I2 + 2Na2S2O3 → 2NaI...

2Cu²⁺ + 4KI → 2CuI + I₂ + 4K⁺ (rxn 1)

I₂ + 2Na₂S₂O₃ → 2NaI + Na₂S₄O₆ (rxn 2)

10.0 mL of a Cu²⁺ solution of unknown concentration was placed in a 250 mL Erlenmeyer flask. An excess of KI solution was added. Indicator was added and the solution was diluted with H₂O to a total volume of 75 mL. The solution was titrated with 0.20 M Na₂S₂O₃. The equivalence point of the titration was reached when 14.45 mL of Na₂S₂O₃ had been added. What is the molar concentration of Cu²⁺ in the unknown solution?

Expert Solution

2Cu²⁺ + 4KI → 2CuI + I₂ + 4K⁺ (rxn 1)

I₂ + 2Na₂S₂O₃ → 2NaI + Na₂S₄O₆ (rxn 2)

Calculating moles of thiosulphate =molarity *volume

= 0.20 mol per L*0.01445 L per mole

=0.00289moles

Calculating moles of I2=0.00289 mole of Na2S2O3*1mole I2/2 mole Na2S2O3

=0.001445 mole of I2

Calculating moles of Cu^2+=0.001445 mole of I2*2 mole of Cu^2+/1 mole of I2

=0.00289 mole of Cu2+

Molarity of the Cu2+=Moles/Volume in L

=0.00289 mole/0.010 L

=0.289 Molar

queen_honey_blossom answered 1 year ago

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