In: Chemistry
1. The Ka of hypochlorous acid (HCLO) is 3.0x10-8. What is the pH at 25 C of an aqueous solution that is .0200 M in HCLO?
2. A .10 M aqueous solution of the weak base B at 25 C has a pH of 8.00. The Value of Kb for B is _____.
1. HClO ---------------------> H^+ (aq) + ClO^-
I 0.02 0 0
C -x +x +x
E 0.02-x +x +x
ka = [H^+][ClO^-]/[HClO]
3*10^-8 = x*x/0.02-x
3*10^-8 *(0.02-x) = x^2
x = 2.45*10^-5
[H^+] = x = 2.45*10^-5 M
PH = -log[H^+]
= -log2.45*10^-5
= 4.6108
2. PH = 8
POH = 14-PH
= 14-8 = 6
POH = 1/2Pkb -1/2logc
6 = 1/2Pkb-1/2log0.1
6 = 1/2Pkb -1/2*-1
6 = 1/2Pkb +0.5
1/2Pkb = 6-0.5
1/2Pkb = 5.5
Pkb = 11
-logKb = 11
Kb = 10^-11 >>>>answer