In: Chemistry
Calculate the pH of a 0.100M NaOCl salt solution. Ka for hypochlorous acid, HOCl, is 3.5x10-8
concentration of NaOCl = 0.100 M
Ka of HOCl = 3.5 x 10^-8
Kb = 2.857 x 10^-7
OCl- + H2O ----------------> HOCl + OH-
0.1 0 0
0.10 - x x x
Kb = x^2 / 0.1 - x
2.857 x 10^-7 = x^2 / 0.1 - x
x = 1.689 x 10^-4
[OH-] = 1.689 x 10^-4 M
pOH = -log (1.689 x 10^-4 ) = 3.77
pH = 10.23