In: Statistics and Probability
A very large trial was conducted to combat the Human Papillomavirus (HPV) on 402,245 consenting adults. 201,867 of the patients were given an experimental vaccine (the treatment group), and 200,378 of them were administered placebos (the placebo group). In the treatment group 41 people contracted HPV, and in the placebo group 124 people contracted HPV. a) Use a 5% significance level to test the claim that this vaccine is effective, and b) create a confidence interval for testing. (Follow all 5 steps in directions.) Note: all requirements are met - the sample proportions are from two independent, simple random samples, and there are at least five successes and five failures.
H0: Null Hypothesis: P1 - P2 0
HA: Alternative Hypothesis: P1 - P2 < 0
n1= 201,867
p1 = 41/201,867 = 0.0002031
n2 = 200,378
p2 = 124/200,378 = 0.0006188
So,
Q = 1 - P = 0.9995898
Test ststistic is:
Z = (0.0002031 - 0.0006188)/0.00006386 = - 6.5096
= 0.05
One Tail - Left Side Test
From Table,critical value of Z = - 1.645
Since calculated value of Z = - 6.509 is less than critical value of Z = - 1.645, thedifference is significant. Rject null hypothesis.
Conclusion:
The data support the claim that this vaccine is effective.
(b)
= 0.05
From Table, critical values of Z = 1.96
Confidence Interval:
(0.0002031 - 0.0006188) (1.96 X 0.00006386)
= - 0.0004157 0.00001252
= ( - 0.0004282, - 0.0004032)