Question

In: Chemistry

Rank the following five salts in order of decreasing solubility, in terms of mass per unit...

Rank the following five salts in order of decreasing solubility, in terms of mass per unit volume.
(The most soluble gets rank 1, the least soluble gets rank 5.)

Hg₂CO₃     (K_sp = 9.00×10^-15; Note: The cation is Hg₂²⁺)
Hg₂Cl₂     (K_sp = 1.10×10^-18; Note: The cation is Hg₂²⁺)
Ca₃(PO₄)₂     (K_sp = 1.30×10^-32)
Ag₃PO₄     (K_sp = 1.80×10^-18)
Ca₅(PO₄)₃OH     (K_sp = 6.80×10^-37)

This is the 2nd time I've posted this question because previously people just listed it in order of the KSP that's given in the question. That is INCORRECT. I need to convert it to mass/volume. I've tried it 4 times and I keep getting the answer wrong.

Expert Solution

1 ) solubility of Hg2CO3 = Ksp^1/2 = (9*10^(-15))^(1/2) = 9.5*10^-8

solubility im mass/volume = 9.5*10^-8*molarmass of Hg2CO3

Molar mass of Hg2CO3 is 461.1889 g/mol

solubility im mass/volume = 9.5*10^-8*461.1889 = 4.38*10^-5 g/L

2) solubility of Hg2Cl2 = (Ksp^1/4)^(1/3) = ((1.1*10^(-18))/4)^(1/3)

= 6.5*10^-7

solubility im mass/volume = 6.5*10^-7*molarmass of Hg2Cl2

Molar mass of Hg2CL2 is 472.09 g/mol

solubility im mass/volume = 6.5*10^-7*472.09

= 0.0003068585 = 3.07*10^-4 g/L

3)

solubility of Ca3(PO4)2 = (Ksp^1/108)^(1/5) = ((1.3*10^(-32))/108)^(1/5)

= 1.64*10^-7

solubility im mass/volume = 1.64*10^-7 *molarmass of Ca3(PO4)2

Molar mass of Ca3(PO4)2 is 310.1767 g/mol

solubility im mass/volume = 1.64*10^-7 *310.1767

= 0.0003068585 = 5.1*10^-5 g/L

4)

solubility of Ag3PO4 = (Ksp^1/27)^(1/4) = ((1.8*10^(-18))/27)^(1/4)

= 1.6*10^-5

solubility im mass/volume = 1.6*10^-5 *molarmass of Ag3PO4

Molar mass of Ag3PO4 is 418.5760 g/mol

solubility im mass/volume = 1.64*10^-7 * 418.5760

= 0.0003068585 = 6.9*10^-5 g/L

5)

solubility of Ca5(PO4)3OH = (Ksp^1/84375)^(1/9) = ((6.8*10^(-37))/84375)^(1/9)

= 2.72*10^-5

solubility im mass/volume = 2.72*10^-5 *molarmass of Ca3(PO4)2

Molar mass of Ca5(PO4)3OH is 502.3114 g/mol

solubility im mass/volume = 2.72*10^-5 *502.3114

= 0.0003068585 = 0.014 g/L

ORDER OF SOLUBILITY

Ca5(PO4)3OH > Hg2Cl2 > Ag3PO4 > Ca3(PO4)2 > Hg2CO3

queen_honey_blossom answered 11 months ago

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