In: Other
a)
The PFD for the same is given below:
b)
Basis : 100 mol of Stream 1
Moles of CO in stream 1 = 50 mol
Fractional conversion of CO in reactor1 = 0.61
Moles of CO converted in reactor1 = 0.61 X 50 = 30.5 mol
Moles of CO unconverted and entering reactor2 = 50 - 30.5 = 19.5 mol
Fractional conversion of CO in reactor2 = 0.79
Moles of CO converted in reactor2 = 0.79 X 19.5 = 15.405 mol
Total moles of CO converted = 30.5 + 15.405 = 45.905 mol
Fractional conversion of CO for the overall process ; F
F = Total moles converted / Total moles fed
F = 45.905 / 50
F = 0.918 (3 significant digits)
c)
From the reaction stoichiometry;
Moles of CO reacted = Moles of H2O reacted = Moles of CO2 formed = Moles of H2O formed
In reactor 1;
Moles of CO reacted = 30.5 mol
Moles of H2O reacted = Moles of CO2 formed = Moles of H2O formed = 30.5
Total moles in stream 2 = Moles of CO left + Moles of H2O left + Moles of CO2 formed + Moles of H2 formed
Total moles in stream 2 = 19.5 + 19.5 + 30.5 +30.5 = 100 mol
Total moles in stream 1 = 100 mol
Therefore;
The ratio of the molar flow rate of stream 2 relative to the molar flow rate of stream 1; R
R = 100 / 100 = 1.00 (3 significant digits)