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In: Physics

If the resolution of a spectrograph is Delta lambda = 10^-12 m, would it be able...

If the resolution of a spectrograph is Delta lambda = 10^-12 m, would it be able to separate the K(alpha) lines of platinum and gold?

Solutions

Expert Solution

Using a formula, we have

E = - (13.6 eV) (Z - 1)2 [(1 / nupper2) - (1 / nlower2)]

The K energies of Pt and Au which are given below as -

For platinum ; E,Pt = - (13.6 eV) (78 - 1)2 [1 / (2)2 - 1 / (1)2)]

E,Pt = 60475.8 eV

For gold ; E,Au = - (13.6 eV) (79 - 1)2 [1 / (2)2 - 1 / (1)2)]

E,Au = 62056.8 eV

We know that, = h c / E

= [(6.63x 10-34 J.s) (3 x 108 m/s)] / [(62056.8 eV) - (60475.8 eV)]

= [(1.989 x 10-25 J.m) / (1581 eV)

converting eV into J :

= [(1.989 x 10-25 J.m) / (2.53 x 10-16 J)]

= 7.86 x 10-10 m

(Since this is larger than 10-12 m, then I will be able to see them as separate)

genius_generous answered 10 months ago
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