Question

In: Chemistry

You need to be able to get an answer of 2.14 x 10-7 M for part...

You need to be able to get an answer of 2.14 x 10-7 M for part c.

A lead ion-selective electrode measured a potential of -33.9 mV when immersed in 50.00 mL of water from a polluted stream. Upon the addition of 0.5 mL          of a 0.105 mM solution of Pb(NO3)2 the potential changed to -11.2 mV.

a)  Write an equation for the response of this electrode, ignoring the response of any other elements (i.e., we will assume selectivity coefficients for non-lead species are all zero) (4 points).

b) Assuming β = 1 in the above equation, write expressions for the response of the electrode to the original sample and to the spiked sample (6 points).

c) Solve the equations you wrote in (b) to find [Pb2+] in the original sample (6 points).

Solutions

Expert Solution

An ideal I.S.E. (Ion-selective electrode) allows only select –ion can be transported thereby creates a

potential difference.

For a charged l species diffusing from a region of activity, A1, to a region of activity, A2, there is a free energy change given by ∆G=-RTln(A1/A2), which is converted to electrical work

-RTln(A1/A2)=-nFE (for positive species)

Since, E=RT/zF ln (A1/A2) =0.05916/z ln(A1/A2) at 298K

Z=charge of species

a) E=0.05916V/2 ln (A1/A2)

A1=activity of Pb2+ in water

A2=activity of Pb2+ in cell electrolyte

For low concentration, activity of Pb2+=[Pb2+]

E= 0.05916V/2 ln{ A (Pb2+) (water)/(Pb2+)(cell electrolyte)}

-33.9 *10^-3 V= 0.05916V/2 ln{ [Pb2+] (water)/[Pb2+](cell electrolyte)}…………………(1)

b)for original sample , when mean ionic activity =1,activity=concentration

-33.9 *10^-3 V= 0.05916V/2 ln{ [Pb2+] (water)/[Pb2+](cell electrolyte)}…………………(1)

For spiked sample,

E= 0.05916V/2 ln{ [Pb2+] (spiked)/[Pb2+](cell electrolyte)}

[Pb2+](spiked)=[Pb2+](water)+ [Pb2+](added)

Moles of Pb2+ (added)=0.105mM*0.5ml=0.105*10^-3 M*0.5/1000L=0.0525 *10^-6 moles

[Pb2+](added)=0.0525 *10^-6 moles

Consequently,

E= 0.05916V/2 ln{ ([Pb2+]water + 1.040 M)/[Pb2+](cell electrolyte)}

-11.2 *10^-3 V = 0.05916V/2 ln{ ([Pb2+]water + 1.040 M)/[Pb2+](cell electrolyte)}………………..(2)

c) equation 1-equation2,

-33.9 *10^-3 V-(-11.2 *10^-3 V) = 0.05916V/2 ln [Pb2+] (water)/ ([Pb2+]water + 0.0525 *10^-6 moles)

-22.7*10^-3 V=0.02958 V ln [Pb2+] (water)/ ([Pb2+]water + 0.0525 *10^-6 moles)

0.879* = ln [Pb2+] (water)/ ([Pb2+]water + 0.0525 *10^-6 moles)

Or,e^(-0.879)= [Pb2+] (water)/ ([Pb2+]water + 0.0525 *10^-6 moles)

Or,0.415=[Pb2+] (water)/ ([Pb2+]water + 0.0525 *10^-6 moles)

Or,2.41=1+(0.0525*10^-6)/[Pb2+]

Or,1.41=0.0525*10^-6/[Pb2+]

Or,[Pb2+]=0.0525*10^-6 moles/1.41=0.0372 *10^-6 moles

[Pb2+]=0.0372 *10^-6 moles/ volume=0.0372 *10^-6 moles/50 ml*1000ml/L=0.744 *10^-6=7.4*10^-7M


Related Solutions

I was able to get questions 1 - 4 answer and only need question 5 and...
I was able to get questions 1 - 4 answer and only need question 5 and its sub-parts. Asymmetric Information and Separating Equilibrium A population has two equal-sized members of "healthy" and "unhealthy" individuals. Members of each type have the same, identical, utility function: U = 20Y0.5 (i.e. 20 x Y raised to the 0.5 power), where Y is annual income.                            Assume each individual, in either group, has disposable income (after normal expenses) of $19,000 a year. If in...
I need an answer for this question with the referance if you get the answer from...
I need an answer for this question with the referance if you get the answer from a website: Question: What is Medicare? Why is it important in our society? Who is entitled to it?
You have been able to get a part-time job in a University laboratory. The group is...
You have been able to get a part-time job in a University laboratory. The group is planning a set of experiments to study the forces between nuclei in order to understand the energy output of the Sun. To do this experiment, you shoot alpha particles from a Van de Graaf accelerator at a sheet of lead. The alpha particle is the nucleus of a helium atom and is made of 2 protons and 2 neutrons. The lead nucleus is made...
Use the following to answer questions 7-10: A = 4.0 m ± 0.2 m, B =...
Use the following to answer questions 7-10: A = 4.0 m ± 0.2 m, B = 3.1 m ± 0.4 m, C = 10.0 m/s ± 0.5 m/s, D = 0.5 s ± 0.01 s Be sure to include appropriate error in your answers Find A+B= C*D= B/D= A/D+C=
You have been able to get a part time job with a medical physics group investigating...
You have been able to get a part time job with a medical physics group investigating ways to treat inoperable brain cancer. One form of cancer therapy being studied uses slow neutrons to knock a particle (either a neutron or a proton) out of the nucleus of the atoms which make up cancer cells. The neutron knocks out the particle it collides with in an inelastic collision. The rest of the nucleus does not move. After a single proton or...
Part A Calculate the pH in 0.020 M H2CO3 (Ka1=4.3×10−7; Ka2=5.6×10−11). Express your answer using two...
Part A Calculate the pH in 0.020 M H2CO3 (Ka1=4.3×10−7; Ka2=5.6×10−11). Express your answer using two decimal places. pH = SubmitMy AnswersGive Up Part B Calculate the concentrations of all species present (H2CO3, HCO−3, CO2−3, H3O+ and OH−) in 0.020 M H2CO3. Express your answers using two significant figures. Enter your answers numerically separated by commas. [H2CO3], [HCO−3], [CO2−3], [H3O+] and [OH−] = M
If you have a 2.14 m aqueous solution of NaHCO3, what is the mole fraction of...
If you have a 2.14 m aqueous solution of NaHCO3, what is the mole fraction of NaHCO3?
If a solution contains 7.5 X 10-8M Cu+2 and 1.0 X 10-7 M Zn+2 will either...
If a solution contains 7.5 X 10-8M Cu+2 and 1.0 X 10-7 M Zn+2 will either metal precipitate as a hydroxide salt if the pH is 8.5? At what concentration of OH- will each metal precipitate?
I need the answer for PART B and PART C of this question: You have recently...
I need the answer for PART B and PART C of this question: You have recently been appointed management accountant for Rugby Coffee Mugs Pty Ltd. The company commenced its operations on 1 July 2019 manufacturing one size coffee mugs with individual club names and club logos of rugby union clubs playing in the New South Wales, Queensland, Victoria and Western Australia local rugby union competition. The company currently does not have any management accounting controls and part of your...
What is the pH of a 1.3 x 10-7 M solution of HCl? Please note that...
What is the pH of a 1.3 x 10-7 M solution of HCl? Please note that you cannot simply add the contribution of H+ ions from the autoproteolysis of water and the contribution from the dissociation of HCl. You will need to use the quadratic equation to solve this problem and report the answer to 4 significant figures.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT