The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probability of each of the following occurring from this population.
a. A random sample of size 32 yielding a sample mean of 76 or more
b. A random sample of size 130 yielding a sample mean of between 72 and 76
c. A random sample of size 220 yielding a sample mean of less than 74.3
In: Math
A population of values has a normal distribution with
μ=81.3μ=81.3 and σ=88.7σ=88.7. You intend to draw a random sample
of size n=168n=168.
Find P80, which is the score separating the
bottom 80% scores from the top 20% scores.
P80 (for single values) =
Find P80, which is the mean separating the
bottom 80% means from the top 20% means.
P80 (for sample means) =
Enter your answers as numbers accurate to 1 decimal place.
************NOTE************ round your answer to ONE digit after
the decimal point! ***********
Answers obtained using exact z-scores or z-scores
rounded to 3 decimal places are accepted.
In: Math
10.7 When people make estimates, they are influenced by anchors to their estimates. A study was conducted in which students were asked to estimate the number of calories in a cheeseburger. One group was asked to do this after thinking about a calorie-laden cheesecake. A second group was asked to do this after thinking about an organic fruit salad. The mean number of calories estimated in a cheeseburger was 780 for the group that thought about the cheesecake and 1,041 for the group that thought about the organic fruit salad. (Data extracted from “Drilling Down, Sizing Up a Cheeseburger's Caloric Heft,” The New York Times, October 4, 2010, p. B2.) Suppose that the study was based on a sample of 20 people who thought about the cheesecake first and 20 people who thought about the organic fruit salad first, and the standard deviation of the number of calories in the cheeseburger was 128 for the people who thought about the cheesecake first and 140 for the people who thought about the organic fruit salad first.
a. State the null and alternative hypotheses if you want to determine whether the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.
b. In the context of this study, what is the meaning of the Type I error?
c. In the context of this study, what is the meaning of the Type II error?
d. At the 0.01 level of significance, is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first?
In: Math
. A manager for an insurance company believes that customers have the following preferences for life insurance products: 40% prefer Whole Life, 10% prefer Universal Life, and 50% prefer Life Annuities. The results of a survey of 310 customers were tabulated. Is it possible to refute the sales manager's claimed proportions of customers who prefer each product using the data?
Product Number Whole 124 Universal 31 Annuities 155
State the null and alternative hypothesis.
What does the null hypothesis indicate about the proportions of fatal accidents during each month?
State the null and alternative hypothesis in terms of the expected proportions for each category.
Find the value of the test statistic. Round your answer to three decimal places.
Find the degrees of freedom associated with the test statistic for this problem.
Find the critical value of the test at the 0.025 level of significance. Round your answer to three decimal places.
Make the decision to reject or fail to reject the null hypothesis at the 0.025 level of significance.
State the conclusion of the hypothesis test at the 0.025 level of significance.
In: Math
Write the null and alternative hypotheses in notation for each of the following statements.
3a. [1 point] The μ for scores on the Wechsler Adult Intelligence Test is 100. |
3b. [1 point] For a population of 25- to 54-year-old women, the mean amount of television watched each day is 4.4 hours. |
3c. [1 point] The mean reaction time of 19-year-old males to a simple stimulus is at least 423.0 milliseconds. |
Given the following information, test whether the population mean is equal to the given value μ0. Provide the following:
4a. [3 points] Two-tailed test, μ0=100, σx̄=25, x̄=70, N=86, α=.01 |
4b. [3 points] Two-tailed test, μ0=87, Sx̄=2.9, x̄=92, N=37, α=.05 |
In: Math
In: Math
Use for Questions 1-7: Hector will roll two fair, six-sided dice at the same time. Let A = the event that at least one die lands with the number 3 facing up. Let B = the event that the sum of the two dice is less than 5.
1. What is the correct set notation for the event that “at least one die lands with 3 facing up and the sum of the two dice is less than 5”?
2. Calculate the probability that at least one die lands with 3 facing up and the sum of the two dice is less than 5.
3. What is the correct set notation for the event that “at least one die lands with 3 facing up if the sum of the two dice is less than 5”?
4. Calculate the probability that at least one die lands with 3 facing up if the sum of the two dice is less than 5.
5. What is the correct set notation for the event that “the sum of the two dice is not less than 5 if at least one die lands with 3 facing up”?
6. Calculate the probability that the sum of the two dice is not less than 5 if at least one die lands with 3 facing up.
7. Are A and B independent? Explain your reasoning
In: Math
A sample of 50 night-school students' ages is obtained in order to estimate the mean age of night-school students. x = 24.3 years. The population variance is 16.
(b) Find the 95% confidence interval for μ. (Give your
answer correct to two decimal places.)
Lower Limit
Upper Limit
(c) Find the 99% confidence interval for μ. (Give your answer correct to two decimal places.)
Lower Limit
Upper Limit
In: Math
Solve the problem.
21) The total home-game attendance for major-league baseball is the sum of all attendees for all stadiums during the entire season. The home attendance (in millions) for a number of years is shown in the table below.
21)
Year
Home Attendance (millions)
1978
40.6
1979
43.5
1980
43.0
1981
26.6
1982
44.6
1983
46.3
1984
48.7
1985
49.0
1986
50.5
1987
51.8
1988
53.2
a) Make a scatterplot showing the trend in home attendance. Describe what you see.
b) Determine the correlation, and comment on its significance.
c) Find the equation of the line of regression. Interpret the slope of the equation.
d) Use your model to predict the home attendance for 1998. How much confidence do you have in this prediction? Explain.
e) Use the internet or other resource to find reasons for any outliers you observe in the
scatterplot.
In: Math
In: Math
In 1997, the average household expenditure for energy was $1,338, according to data obtained from the U.S. Department of Energy. An economist claims that energy usage today is different from its 1997 level. In a random sample of 36 households, the economist found the mean expenditure, adjusted for inflation, for energy in 2004 to be $1,423. with a sample standard deviation s = 360.
At a 95% level of confidence (α = .05), we wish to test the economists claim.
1. State the Null Hypothesis and Alternate Hypothesis for this experiment.
a. |
Ho: p = $1,338 Ha: p not = $1,423 |
|
b. |
Ho: µ <= $1,338 Ha: µ > $1,338 |
|
c. |
Ho: µ = $1,423 Ha: µ not = $1,423 |
|
d. |
Ho: µ = $1,338 Ha: µ not = $1,338 |
2.What is the p-value and decision of this research?
a. |
p-value = .165; Do Not Reject Ho. |
|
b. |
p-value = .165; Reject Ho. |
|
c. |
p-value = .0825; Do Not Reject Ho. |
|
d. |
P-value = .0825; Reject Ho. |
3.State the conclusion.
a. |
With 95% Confidence, there is sufficient evidence to show that energy usage today is different from its 1997 level. |
|
b. |
With 95% Confidence, there is insufficient evidence to show that energy usage today is different from its 1997 level. |
|
c. |
With 95% Confidence, there is sufficient evidence to show that energy usage today is greater than its 1997 level. |
|
d. |
With 95% Confidence, there is insufficient evidence to show that energy usage today is greater than its 1997 level. |
4.State the Type I error for this Hypothesis Test and the corresponding probability of a Type I error occurring in this experiment.
a. |
Conclude energy usage is not different, but it really is. Probability = .05 |
|
b. |
Conclude energy usage is not different, but it really is. Probability = .95 |
|
c. |
Concluded energy usage is different, but it really isn't. Probability = .95 |
|
d. |
Conclude energy usage is different, but it really isn't. Probability = .05 |
5.In order to decrease the probability of a Type I error, we would do the following before conducting this experiment:
a. |
Increase the Confidence Level of the Hypothesis Test, thereby decreasing alpha. |
|
b. |
Decrease the Confidence Level of the Hypothesis Test, thereby decreasing alpha. |
|
c. |
Increase the sample size from 36. |
|
d. |
Decrease the sample size from 36. |
In: Math
Below are means, standard deviations, and sample sizes of three different data sets. Estimate the 90% confidence interval for dataset A, 95% for data set B, and 99% for set C.
Set A: mean=6300, standard deviation= 300, n=200
Set B: mean=65, standard deviation= 15, n=75
Set C: mean=93, standard deviation= 37, n=200
In: Math
Kroger runs Buy One Get One (BOGO) promotions every year to promote charcoal for Memorial Day. Their data indicates that 76 customers per day per store purchase this deal every spring and the standard deviation historically is 12 customers. Assume that the population is normally distributed. What is the probability that for a random sample of 15 days, at least 70 customers per day will buy charcoal with the BOGO?
1) 0.6915
2) 0.9772
3) 0.0262
4)0.9738
In: Math
The IQs of students at Wilson Elementary School were measured recently and found to be normally distributed with a mean of 110 and a standard deviation of 13. What is the probability that a student selected at random will have the following IQs? (Round your answers to four decimal places.)
(a) 140 or higher
(b) 115 or higher
(c) between 110 and 115
(d) 100 or less
In: Math
Suppose the installation time in hours for a software on a laptop has probability density function f(x) = (4/3) (1 − x3 ), 0 ≤ x ≤ 1.
(a) Find the probability that the software takes between 0.3 and 0.5 hours to be installed on your laptop.
(b) Let X1, . . . , X30 be the installation times of the software on 30 different laptops. Assume the installation times are independent. Find the probability that the average installation time is between 0.3 and 0.5 hours. Cite the theorem you use.
(c) Instead of taking a sample of 30 laptops as in the previous question, you take a sample of 60 laptops. Find the probability that the average installation time is between 0.3 and 0.5 hours. Cite the theorem you use.
In: Math