In: Math
Identify the distribution and give a symbolic expression for each indicated probability, identifying parameters. Then use Mathematica or Excel to evaluate the indicated probabilities.
1. Chemistry -41
Biology -81
Total = 41+81= 122
(a) Total number of cases of selecting 7 students =
Favorable number of cases =
*
Probability of selecting 2 chem and 5 bio students= favorable number of cases / total number of cases
=
*
= 0.3137
Note : using excel " =COMBIN(41,2)*COMBIN(81,5)/COMBIN(122,7)"
(b) Out of 7 selected ,
If chem- 1 , then bio -6
If chem 2 , then bio - 5
.....
If chem -7 , bio -0
Probability of selecting atleast one chem major
=
*
+ ....... +
*
= 0.9481
chem | bio | Probability |
1 | 6 | 0.1986477 |
2 | 5 | 0.3136543 |
3 | 4 | 0.2647731 |
4 | 3 | 0.128992 |
5 | 2 | 0.0362484 |
6 | 1 | 0.0054373 |
7 | 0 | 0.0003356 |
0.9480886 |
formula for each probability is calculated as " =COMBIN(41,A13)*COMBIN(81,B13)/COMBIN(122,7)"
where A13 cell represents chem, B13 cell represents bio
2. (a)Using Binomial probability law
Let X be the number of horses disqualified
X follow Binomial with n = 19 , p = 0.09
P(X=0) =0.1666
Note :Using excel " =BINOM.DIST(0,19,0.09,FALSE)"
(b) To find the probability that first disqualified horse in is 23 rd race
We first find no disqualified horse in 22 races
and then joint probability of no disqualified horse in 22 races and probability of disqualifying a horse
n | P(X=0) | P(X=0)*0.09 | |
22 | 0.125577 | 0.01130194 | |
23 | 0.114275 | 0.01028477 | |
24 | 0.10399 | 0.00935914 | |
25 | 0.094631 | 0.00851682 | |
26 | 0.086114 | 0.0077503 | |
27 | 0.078364 | 0.00705278 | |
28 | 0.071311 | 0.00641803 | |
29 | 0.064893 | 0.0058404 | |
30 | 0.059053 | 0.00531477 | |
0.07183895 |
Thus required probability = 0.0718