Questions
This exercise has two parts. Please respond to both. The calculation formulas and procedures for both...

This exercise has two parts. Please respond to both. The calculation formulas and procedures for both parts are included in the mini-lecture titled “Rates and Percentages” Part One The Mayors of two small towns that adjoin a large community have engaged in an argument on which of their cities is safer, with respect to its crime rate. City A has a residential population of 123,000 people and reported 185 violent crimes. City B has a residential population of 84,000 people and reported 135 violent crimes. Answer the following questions. 1. What is the reported crime rate per 100,000 residents in both cities? 2. Based on your responses to the previous question, which city has the lowest crime rate? Part Two Last year. 135 vehicles were reported stolen in the City of Bigton. This year, 185 vehicles were reported stolen in the City of Bigton. What is the percent change in reported stolen vehicles from last year to this year in the City of Bigton?

In: Math

1. The waiting times​ (in minutes) of a random sample of 21 people at a bank...

1. The waiting times​ (in minutes) of a random sample of 21 people at a bank have a sample standard deviation of 3.5 minutes. Construct a confidence interval for the population variance sigma squared and the population standard deviation sigma. Use a 99 % level of confidence. Assume the sample is from a normally distributed population. What is the confidence interval for the population variance sigma squared​?

2.You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If​ convenient, use technology to construct the confidence intervals. A random sample of 55 home theater systems has a mean price of ​$113.00. Assume the population standard deviation is ​$15.20.

In: Math

The Table in my homework question below is completely wrong. I am not sure where I...

The Table in my homework question below is completely wrong. I am not sure where I went wrong in my calculations but coud you rework this question and answer the parts below??

Here are earnings per share for two companies by quarter from the first quarter of 2009 through the second quarter of 2012. Forecast earnings per share for the rest of 2012 and 2013. Use exponential smoothing to forecast the third period of 2012, and the time series decomposition method to forecast the last two quarters of 2012 and all four quarters of 2013. (It is much easier to solve this problem on a computer spreadsheet so you can see what is happening.)


EARNINGS PER SHARE

QUARTER COMPANY A COMPANY B
2009 I $ 1.68 $ 0.21         
II 2.36 0.23         
III 1.21 0.21         
IV 1.30 0.35         
2010 I 1.66 0.20         
II 2.08 0.36         
III 1.31 0.37         
IV 0.34 0.48         
2011 I 0.34 0.35         
II –0.19 (loss) 0.49         
III –0.87 (loss) 0.51         
IV 0.24 0.52         
2012 I –1.65 (loss) 0.31         
II 0.37 0.52         


a.

For the exponential smoothing method, choose the first quarter of 2009 as the beginning forecast. Make two forecasts: one with α = 0.20 and one with α = 0.30. (Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.)

For the exponential smoothing method, choose the first quarter of 2009 as the beginning forecast. Make two forecasts: one with α = 0.20 and one with α = 0.30. (Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.)

Company A

Company B

          Quarter Forecast
α = 0.20
Forecast
α = 0.30
Forecast
α = 0.20
Forecast
α = 0.30
2009    I                
           II                
           III                
           IV                
2010     I                
            II                
           III                
            IV                
2011     I                
            II                
            III                
            IV                
2012      I                
             II                
            III                


b-1.

Calculate the MAD for each forecast using data starting with second quarter of 2009 through second quarter of 2012. (Round your answers to 3 decimal places.)


MAD

    Company A     Company B
  α = 0.20      
  α = 0.30      


b-2.

Using the MAD method of testing the forecasting model's performance, plus actual data from 2009 through the second quarter of 2012, how well did the model perform?


  Based upon MAD, (Click to select)0.30.2 performs better than an α of (Click to select)0.20.3.

In: Math

Is there sufficient evidence to conclude that there is a mean difference in mile time for...

Is there sufficient evidence to conclude that there is a mean difference in mile time for runners when they had coffee with breakfast vs without?

PAIRED SAMPLES TEST
Pair 1 coffee-nocoffee
Mean=-.31585
Std. Deviation= .52660
Std. Error mean=.08326
Lower=-.48427
Upper= -.14744
t= -3.793
df=39
Sig. (2-tailed)=.001

a. Should they reject or retain? Give numerical justification
b. Calculate the effect size
c. Interpret the effect size in the context of the situation

In: Math

Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate:...

Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate: (a) find the critical value tα/2​, ​(b) find the critical value zα/2​, or​ (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn​ girls: n=151 x = 29.1 hg S =7.6 hg The confidence level is 95​%. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. t Subscript alpha divided by 2 tα/2 = ​(Round to two decimal places as​ needed.) B. z Subscript alpha divided by 2 zα/2 = ​(Round to two decimal places as​ needed.) C. Neither the normal distribution nor the t distribution applies.

In: Math

Pls answer all three parts for UPVOTE Data set: Students Outside US Stu ID Age GPA...

Pls answer all three parts for UPVOTE

Data set:

Students Outside US

Stu ID Age GPA Hrs spend on sch wrk
3 48 4.00 7
6 47 2.79 14
9 45 3.48 5
12 19 4.00 30
15 24 3.10 10
18 34 3.24 2
21 44 36.00 6
24 19 2.85 7
27 19 2.80 10
30 27 3.40 8
33 28 2.90 16
36 27 3.40 8
39 28 2.90 16
42 21 2.9 4
45 20 2.50 6
48 23 3.3 18
51 41 3.80 7
54 21 2.60 26
57 39 5
60 18 3.10 12
63 28 3.70 20
66 35 8
69 37 2.80 6
72 21 N/A 21
75 20 3.00 4
78 30 3.50 6
81 21 3.1 4
84 21 3.20 3
87 37 2.86 3
90 19 3.30 12

Students in US:

Stu ID Age GPA Hrs spend on sch wrk
175 20 3.20 10
178 20 2.40 12
181 17 3.98 6
184 20 3.00 15
187 27 2.20 6
190 19 3.00 7
193 3.10 15
196 20 6
199 43 3.67 12
202 44 3.80 10
205 26 3.80 4
208 25 2.50 5
211 21 3.72 10
214 29 2.54 4
217 33 3.85 21
220 18 3.00 5
223 21 3.00 6
226 19 3.00 5
229 26 3.00 4
232 19 2.81 4
235 19 3.00 6
238 28 3.50 10
241 19 4.00 12
244 20 3.20 2
247 21 9
250 20 2.51 3
253 20 3.20 5
256 23 2
259 20 3.10 27
262 26 2.50 8

a) Construct a 5-number summary and boxplot using the variable “hours spent on school work at home” for both groups.

b) Compare the means for both groups to answer the research questions in the first paragraph. Which group has a higher mean GPA? Which group spends more time on their homework? What conclusions can you draw about students who were born in the USA and those who were born outside the USA based on this analysis?

c) Identify any outliers in both groups

In: Math

Justin is interested in buying a digital phone. He visited 9 stores at random and recorded...

Justin is interested in buying a digital phone. He visited 9 stores at random and recorded the price of the particular phone he wants. The sample of prices had a mean of 337.63 and a standard deviation of 30.04.

(a) What t-score should be used as the multiplier for a 95% confidence interval for the mean, ?, of the distribution?
t =

(b) Calculate a 95% confidence interval for the mean price of this model of digital phone:
(Enter the smaller value in the left answer box.)
___ to ___

In: Math

The Pew Research Center Internet Project conducted a survey of 657 Internet users. This survey provided...

The Pew Research Center Internet Project conducted a survey of 657 Internet users. This survey provided a variety of statistics on them. If required, round your answers to four decimal places.

(a) The sample survey showed that 90% of respondents said the Internet has been a good thing for them personally. Develop a 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally.

___ to ___

(b) The sample survey showed that 67% of Internet users said the Internet has generally strengthened their relationship with family and friends. Develop a 95% confidence interval for the proportion of respondents who say the Internet has strengthened their relationship with family and friends.

___ to ___

(c) Fifty-six percent of Internet users have seen an online group come together to help a person or community solve a problem, whereas only 25% have left an online group because of unpleasant interaction. Develop a 95% confidence interval for the proportion of Internet users who say online groups have helped solve a problem.

__ to __

In: Math

The types of browse favored by deer are shown in the following table. Using binoculars, volunteers...

The types of browse favored by deer are shown in the following table. Using binoculars, volunteers observed the feeding habits of a random sample of 320 deer.

Type of Browse Plant Composition
in Study Area
Observed Number of Deer
Feeding on This Plant
Sage brush           32% 105                
Rabbit brush           38.7% 125                
Salt brush           12% 46                
Service berry             9.3% 22                
Other             8% 22                

Use a 5% level of significance to test the claim that the natural distribution of browse fits the deer feeding pattern.

(a) What is the level of significance?


State the null and alternate hypotheses.

H0: The distributions are different.
H1: The distributions are the same.

H0: The distributions are the same.
H1: The distributions are the same.    

H0: The distributions are the same.
H1: The distributions are different.

H0: The distributions are different.
H1: The distributions are different.


(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)


Are all the expected frequencies greater than 5?

Yes

No    


What sampling distribution will you use?

binomial

Student's t    

uniform

normal

chi-square


What are the degrees of freedom?


(c) Estimate the P-value of the sample test statistic.

P-value > 0.100

0.050 < P-value < 0.100    

0.025 < P-value < 0.050

0.010 < P-value < 0.025

0.005 < P-value < 0.010

P-value < 0.005


(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?

Since the P-value > α, we fail to reject the null hypothesis.

Since the P-value > α, we reject the null hypothesis.    

Since the P-value ≤ α, we reject the null hypothesis.

Since the P-value ≤ α, we fail to reject the null hypothesis.


(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, the evidence is sufficient to conclude that the natural distribution of browse does not fit the feeding pattern.

At the 5% level of significance, the evidence is insufficient to conclude that the natural distribution of browse does not fit the feeding pattern.

In: Math

Historically, the time needed for college students to complete their degree follows a normal distribution with...

Historically, the time needed for college students to complete their degree follows a normal distribution with a mean of 4 years and a standard deviation of 1.2 years. You wish to see if the mean time m has changed in recent years, so you collect information from 5 recent college graduates.

                                                       4.25      4            3.75       4.5 5

Is there evidence that the mean time is different from 4 years?

a. Check the needed conditions for both the test statistic and confidence interval. (Do not do a stemplot.)

b. State Ho and Ha

c. Calculate the test statistic (if applicable – state the degrees of freedom)

d. Find the p-value

e. What is the conclusion for this problem? Do you reject Ho?

f. Calculate the 98% confidence interval.

g. Interpret this confidence interval

In: Math

QUESTION 2 Part 1 In a survey of 800 college students in the United States, 608...

QUESTION 2

Part 1

In a survey of 800 college students in the United States, 608 indicated that they believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action. Assuming that the sample is representative of college students in the United States, construct a 95% confidence interval for the proportion of college students who have this belief. (Use a table or technology. Round your answers to three decimal places.)

(___,___)

PART B

Interpret the interval. Chose 1

A. We are 95% confident that the mean number of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.

B. There is a 95% chance that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.    

C. There is a 95% chance that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls directly in the middle of this interval.

D. We are 95% confident that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.

E. We are 95% confident that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls directly in the middle of this interval.

In: Math

Cultivated amaranth grains (Amaranthus caudatus) come in three colors: black, brown, and pale. Geneticists asked whether...

Cultivated amaranth grains (Amaranthus caudatus) come in three colors: black, brown, and pale. Geneticists asked whether this phenotype could result from a dominant epistatic control. Crossing black-seeded and pale-seeded A. caudatus populations (homozygous lines) gave the following counts of black, brown, and pale seeds in the second generation (F2).

Seed coat color

Black

Brown

Pale

Seed count

344

82

31

In genetics, dominant epistasis should lead to 12/16 of all such seeds being black, 3/16 Brown, and 1/16 pale. Do the experimental data above support the conclusion that seed coat color in cultivated amaranth grains is due to dominant epistasis?

Please find the Ho, Ha, test statistic, df, exact probability of the test statistic, and conclusion relative to the hypothesis. Is this a 1-tailed or 2-tailed test? Use Excel functions and math calculations, please.

I think you Chi-Squared for this, but I am not sure.

In: Math

Why will a design for a Graeco-Latin square of size 3 not work well?

Why will a design for a Graeco-Latin square of size 3 not work well?

In: Math

Pick a profession, identify events that might affect the variation ( you must include all three...

Pick a profession, identify events that might affect the variation ( you must include all three ; cyclical, seasonal and irregular ) of the secular trend. List at least three ways that this information could be beneficial to the industry.

In: Math

To test whether the mean time needed to mix a batch of material is the same...

To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.

Manufacturer

1 2 3
21 27 24
27 24 18
21 30 24
18 27 18
  1. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use = .05.

    Compute the values below (to 2 decimals, if necessary).
    Sum of Squares, Treatment
    Sum of Squares, Error
    Mean Squares, Treatment
    Mean Squares, Error


    Calculate the value of the test statistic (to 2 decimals).



    The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10

    What is your conclusion?

    SelectConclude the mean time needed to mix a batch of material is not the same for all manufacturersDo not reject the assumption that mean time needed to mix a batch of material is the same for all manufacturers
  2. At the = .05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3.

    Calculate Fisher's LSD Value (to 2 decimals).



    What is your conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3?

    SelectCannot conclude there is a difference in the mean time for these manufacturersThese manufacturers have different mean times

In: Math