Question

This exercise has two parts. Please respond to both. The calculation formulas and procedures for both parts are included in the mini-lecture titled “Rates and Percentages” Part One The Mayors of two small towns that adjoin a large community have engaged in an argument on which of their cities is safer, with respect to its crime rate. City A has a residential population of 123,000 people and reported 185 violent crimes. City B has a residential population of 84,000 people and reported 135 violent crimes. Answer the following questions. 1. What is the reported crime rate per 100,000 residents in both cities? 2. Based on your responses to the previous question, which city has the lowest crime rate? Part Two Last year. 135 vehicles were reported stolen in the City of Bigton. This year, 185 vehicles were reported stolen in the City of Bigton. What is the percent change in reported stolen vehicles from last year to this year in the City of Bigton?

Answer 1

Part 1:

Population of city A = 123000

Number of violent crimes are reported = 185.

Hence Crime rate for per 100000 residents in City A is

= (185 * 100000) / 123000

= 150.4065

Number of crime rate for 100000 residents in city A is 150.4065

Population of city B= 84000

Number of violent crimes are reported = 135.

Hence Crime rate for per 100000 residents in City B is

= (135 * 100000) / 84000

= 160.7143

Number of crime rate for 100000 residents in city B is 160.7143.

Since ( 160.7143 > 150.4065) Hence city A has lowest crime rate .

Part 2:

Number of vehicles were reported in stolen in the City of Bigton in last year. = 135

Number of vehicles were reported in stolen in the City of Bigton in Current year. = 185.

Percent change in reported stolen vehicles from last year to this year in the City of Bigton is

= ( 185 /135) *100

= 137.04%

Hence percentage change in reported stolen vehicles in increased by 37.04% from last year to this year.