Question

In: Math

Is there sufficient evidence to conclude that there is a mean difference in mile time for...

Is there sufficient evidence to conclude that there is a mean difference in mile time for runners when they had coffee with breakfast vs without?

PAIRED SAMPLES TEST
Pair 1 coffee-nocoffee
Mean=-.31585
Std. Deviation= .52660
Std. Error mean=.08326
Lower=-.48427
Upper= -.14744
t= -3.793
df=39
Sig. (2-tailed)=.001

a. Should they reject or retain? Give numerical justification
b. Calculate the effect size
c. Interpret the effect size in the context of the situation

Solutions

Expert Solution


milcah answered 1 year ago
Next > < Previous

Related Solutions

1. Is there sufficient evidence to conclude that there is a difference in the mean age...
1. Is there sufficient evidence to conclude that there is a difference in the mean age of male customers vs female customers? DATA Equal variances assumed F= 1.572 Sig=.210 t= .370 df= 4998 Sig. (2- tailed)= .712 Mean difference= .185 Std. Error difference= .501 Lower= -.797 Upper= 1.167 95% confidence Interval Equal variances not assumed t= .370 df= 4992. 696 Sig. (2-tailed)= .712 Mean difference= .185 Std. Error difference= .501 Lower= .797 Upper= 1.167 a. should they reject or retain?...
1. Is there sufficient evidence to conclude that there is a difference in the mean number...
1. Is there sufficient evidence to conclude that there is a difference in the mean number of hours of tv watched for those that reported active lifestyle vs those that did not? DATA: Equal variances assumed F=4.997 Sig.=.025 t= .420 df=4998 Sig. (2-tailed)= .675 Mean difference= .49823 Std. Error difference= .51551 Lower=-.51256 Upper= 1.50903 Equal Variances not assumed t=-.421 df= 4966.401 Sig. (2-tailed)=.674 Mean difference= -.062 Std. Error difference= .146 Lower=-.348 Upper= .225 95% confidence interval a. should they reject...
marriages Mean: 182916.67 standard Deviation: 43928.57 n= 12 Determine if there is sufficient evidence to conclude...
marriages Mean: 182916.67 standard Deviation: 43928.57 n= 12 Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500 in the United States and territories at the .05 level of significance. 1. Clearly state a null and alternative hypothesis 2. Give the value of the test statistic 3. Report the P-Value 4. Clearly state your conclusion (Reject the Null or Fail to Reject the Null) 5. Explain what your conclusion means in...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in the United States and territories at the 0.10 level of significance. Summary Table for Deaths AVERAGE 4,292 MEDIAN 3,085 STANDARD DEVIATION 4292.71585 MAX 20,895 MIN 316 Clearly state a null and alternative hypothesis Give the value of the test statistic n=52 Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to...
Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in the United States and territories at the 0.10 level of significance. N=52 Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data. Summary Table for Deaths Mean 4,001 Median 2,961 Standard Deviation...
Determine if there is sufficient evidence to conclude the average amount of marriages is greater or...
Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500 in the United States and territories at the .05 level of significance. N=52 Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data. Summary Table for Marriages Mean 3,801 Median 3,000...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. Summary Table for Live Births AVERAGE 6,833 MEDIAN 4,781 STANDARD DEVIATION 8039.02237 MAX 45,231 MIN 537 Clearly state a null and alternative hypothesis Give the value of the test statistic n= 52 Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion...
Determine if there is sufficient evidence to conclude the average amount of divorces is less than...
Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data. using this data sample size is 52 Summary...
Determine if there is sufficient evidence to conclude the average amount of divorces is greater than...
Determine if there is sufficient evidence to conclude the average amount of divorces is greater than or equal to 3000 in the United States and territories at the 0.05 level of significance N=52. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data. Summary Table for Divorces Mean 1,399 Median...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000...
Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance. Mean-6206, Median- 4260.5, Standard Deviation- 7419.46802, Min- 444, Max-42,836 Determine if there is sufficient evidence to conclude the average amount of deaths is equal to 6000 in the United States and territories at the 0.10 level of significance.Mean-3877, Median- 2698, Standard Deviation- 3950.91464, Min- 323, Max-7684 Determine if there is sufficient evidence...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT