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Q1. Define the following terms:
A. Contingency table (Introduction to
Biostatistics)
B. Chi-square test (Introduction to
Biostatistics)
Q2. List the assumptions required to perform a chi-square test?
(Introduction to Biostatistics)
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In: Math
In: Math
Suppose a sample of 49 paired differences that have been randomly selected from a normally distributed population of paired differences yields a sample mean d⎯⎯ =4.1d¯ =4.1 of and a sample standard deviation of sd = 6.8.
(a) Calculate a 95 percent confidence interval for µd = µ1 – µ2. Can we be 95 percent confident that the difference between µ1 and µ2 is greater than 0? (Round your answers to 2 decimal places.)
Confidence interval = [ , ] ; (Click to select)YesNo
(b) Test the null hypothesis H0: µd = 0 versus the alternative hypothesis Ha: µd ≠ 0 by setting α equal to .10, .05, .01, and .001. How much evidence is there that µd differs from 0? What does this say about how µ1 and µ2 compare? (Round your answer to 3 decimal places.)
t = |
Reject H0 at ? equal to (Click to select)all test valuesno test values0.10.1,and 0.0010.05 (Click to select)nosomestrongvery strongextremely strong evidence that µ1 differs from µ2. |
(c) The p-value for testing H0: µd < 3 versus Ha: µd > 3 equals .1316. Use the p-value to test these hypotheses with α equal to .10, .05, .01, and .001. How much evidence is there that µd exceeds 3? What does this say about the size of the difference between µ1 and µ2? (Round your answer to 3 decimal places.)
t = ; p-value |
Reject H0 at ? equal to (Click to select)no test values0.050.10 and 0.05.10 .05 .01 and .0010.05 and 0.01, (Click to select)Very strongextremely strongsomeStrongNo evidence that µ1 and µ2 differ by more than 3. |
rev: 07_14_2017_QC_CS-93578, 12_08_2018_QC_CS-150993
In: Math
You wish to test the following claim (Ha) at a significance
level of α=0.001.
Ho:μ=57.4
Ha:μ>57.4
You believe the population is normally distributed and you know the
standard deviation is σ=6.6. You obtain a sample mean of M=59.7 for
a sample of size n=72.
What is the critical value for this test? (Report answer accurate
to three decimal places.)
critical value =
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
The test statistic is...
in the critical region
not in the critical region
This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that...
There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 57.4.
There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 57.4.
The sample data support the claim that the population mean is greater than 57.4.
There is not sufficient sample evidence to support the claim that the population mean is greater than 57.4.
In: Math
The Laurenster Corporation needs to set up an assembly line to produce a new product. The fol- lowing table describes the relationships among the activities that need to be completed for this product to be manufactured.
DAYS IMMEDIATE
ACTIVITY a m b PREDECESSORS
A 3 6 6 —
B 5 8 11 A
C 5 6 10 A
D 1 2 6 B, C
E 7 11 15 D
F 7 9 14 D
G 6 8 10 D
H 3 4 8 F, G
I 3 5 7 E, F, H
a) Develop a project network for this problem.
b) Determine the expected duration and variance for each activity.
c) Determine the ES, EF, LS, LF, and slack time for each activity. Also determine the total
project completion time and the critical path(s).
d) Determine the probability that the project will be completed in 34 days or less.
e) Determine the probability that the project will take longer than 29 days.
*****PLEASE SHOW ME HOW TO CALCULATE IN EXCEL QM...FORMULAS' INCLUDED****
In: Math
Given f(x,y) = 2 ; 0< x ≤ y < 1
a. Prove that f(x,y) is a joint pdf.
b. Find the correlation coefficient of X and Y.
In: Math
1.
John has two jobs. For daytime work at a jewelry store he is paid $15,000 per month,
plus a commission. His monthly commission is normally distributed with mean $10,000
and standard deviation $2,000. John's income levels from these two sources are
independent of each other. Use this information to answer the following questions:
a) for a given month, what is the probability that John's commission from the jewelry store is less than $13,000?
b) for a given month, what is the probability that John's commission from the jewelry store is at least $12,000?
c) for a given month, what is the probability that John's commission from the jewelry store is between $11,000 and $12,000?
d) the probability is 0.95 that John's commission from the jewelry store is at least how much in a given month?
e) the probability is 0.75 that John's commission from the jewelry store is less than?
f) how much in a given month?
2) The amount of time a bank teller spends with each customer has a population mean m = 3.10 minutes and standard deviation s = 0.40 minute. If a random sample of 16 customers is selected.
What is the distribution of the mean amount of time for the samples?
What is the probability that the average time spent per customer will be at least 3 minutes?
There is an 85% chance that the sample mean will be below how many minutes?
If a random sample of 64 customers is selected, there is an 85% chance that the sample mean will be below how many minutes?
*for the solution for problem 2 please say how to do in excel using phstat?
In: Math
What is considered an outbreak? How to investigate a disease outbreak? Your paper should be 3-4 pages in length
In: Math
A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 28 subjects had a mean wake time of 96.9 min and a standard deviation of 42.3 min. Assume that the 28 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. nothing minless thansigmaless than nothing min (Round to two decimal places as needed.)
In: Math
The fill amount of bottles of a soft drink is normally distributed, with a mean of 1.01.0 literliter and a standard deviation of 0.040.04 liter. Suppose you select a random sample of 2525 bottles. a. What is the probability that the sample mean will be between 0.990.99 and 1.01.0 literliter? b. What is the probability that the sample mean will be below 0.980.98 literliter? c. What is the probability that the sample mean will be greater than 1.011.01 liters? d. The probability is 9999% that the sample mean amount of soft drink will be at least how much? e. The probability is 9999% that the sample mean amount of soft drink will be between which two values (symmetrically distributed around the mean)? a. The probability is nothing. (Round to three decimal places as needed.) b. The probability is nothing. (Round to three decimal places as needed.) c. The probability is nothing. (Round to three decimal places as needed.) d. There is a 9999% probability that the sample mean amount of soft drink will be at least nothing liter(s). (Round to three decimal places as needed.) e. There is a 9999% probability that the sample mean amount of soft drink will be between nothing liter(s) and nothing liter(s). (Round to three decimal places as needed. Use ascending order.)
PLEASE SHOW ME HOW TO DO IT IN EXCEL, THANKS
In: Math
The World Bank collected data on the percentage of GDP that a country spends on health expenditures ("Health expenditure," 2013) and also the percentage of woman receiving prenatal care ("Pregnant woman receiving," 2013). The data for the countries where this information is available for the year 2011 are in table #10.1.8.
a.) Test at the 5% level for a correlation between percentages spent on health expenditure and the percentage of woman receiving prenatal care.
b.) Find the standard error of the estimate.
c.) Compute a 95% prediction interval for the percentage of woman receiving prenatal care for a country that spends 5.0 % of GDP on health expenditure.
HEALTH EXPENDITURE (% of GDP) |
Prenatal Care (%) |
9.6 |
47.9 |
3.7 |
54.6 |
5.2 |
93.7 |
5.2 |
84.7 |
10.0 |
100.0 |
4.7 |
42.5 |
4.8 |
96.4 |
6.0 |
77.1 |
5.4 |
58.3 |
4.8 |
95.4 |
4.1 |
78.0 |
6.0 |
93.3 |
9.5 |
93.3 |
6.8 |
93.7 |
6.1 |
89.8 |
In: Math
Following the crackdown, the sheriff takes a random sample (n=84) of vehicle speeds on the road way. His sample data: mean is 63 mph, sample SD is 4 mph.
In: Math
1.) The file cats.csv contains a data set consisting of the body weight (in kilograms) and heart weight (in grams) for 12 cats. Test at the 5% significance level that a positive linear relationship exists between the body weight of cat and their mean heart weight. Provides all parts of the test including hypotheses, test statistic, p-value, decision, and interpretation.
2.) The file cats.csv contains a data set consisting of the body weight (in kilograms) and heart weight (in grams) for 12 cats. Construct and interpret a 90% confidence interval for β1
cats.csv file is
bwt | hwt |
2.6 | 9.8 |
3.8 | 16.3 |
3.7 | 16.2 |
3.4 | 16.3 |
2 | 7.7 |
3.8 | 13.3 |
2.5 | 10.5 |
2.1 | 8.7 |
2.1 | 7.3 |
3.1 | 13.7 |
3.6 | 14.4 |
3.2 | 13.4 |
In: Math
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 72 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at
random is between 71 and 73 inches tall? (Round your answer to four
decimal places.)
(b) If a random sample of twelve 18-year-old men is selected, what
is the probability that the mean height x is between 71
and 73 inches? (Round your answer to four decimal places.)
(c) Compare your answers to parts (a) and (b). Is the probability
in part (b) much higher? Why would you expect this?
The probability in part (b) is much higher because the standard deviation is larger for the x distribution.
The probability in part (b) is much lower because the standard deviation is smaller for the x distribution.
The probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
The probability in part (b) is much higher because the mean is larger for the x distribution
The probability in part (b) is much higher because the mean is smaller for the x distribution.
In: Math
1.) The file cats.csv contains a data set consisting of the body weight (in kilograms) and heart weight (in grams) for 12 cats. Give the estimated regression line using the body weight as the predictor variable (x-variable) and the heart weight as the response variable (y-variable). Also, provide interpretations in terms of the problem for the slope and the y-intercept.
2.) The file cats.csv contains a data set consisting of the body weight (in kilograms) and heart weight (in grams) for 12 cats. Give the correlation coefficient and the coefficient of determination. Provide interpretations for both of these.
3.) The file cats.csv contains a data set consisting of the body weight (in kilograms) and heart weight (in grams) for 12 cats. Give the point estimate and 99% confidence interval for the mean heart weight of cats whose body weights are 2.4 kilograms. Give an interpretation for the 99% confidence interval.
cats.csv file is
bwt | hwt |
2.6 | 9.8 |
3.8 | 16.3 |
3.7 | 16.2 |
3.4 | 16.3 |
2 | 7.7 |
3.8 | 13.3 |
2.5 | 10.5 |
2.1 | 8.7 |
2.1 | 7.3 |
3.1 | 13.7 |
3.6 | 14.4 |
3.2 | 13.4 |
In: Math