In: Math
You wish to test the following claim (Ha) at a significance
level of α=0.001.
Ho:μ=57.4
Ha:μ>57.4
You believe the population is normally distributed and you know the
standard deviation is σ=6.6. You obtain a sample mean of M=59.7 for
a sample of size n=72.
What is the critical value for this test? (Report answer accurate
to three decimal places.)
critical value =
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
The test statistic is...
in the critical region
not in the critical region
This test statistic leads to a decision to...
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that...
There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 57.4.
There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 57.4.
The sample data support the claim that the population mean is greater than 57.4.
There is not sufficient sample evidence to support the claim that the population mean is greater than 57.4.
Solution:
Given:
We have to test the following claim (Ha) at a significance level of α=0.001.
Ho: μ =
57.4
Ha: μ > 57.4
The population is normally distributed
Population standard deviation = σ = 6.6.
Sample mean = M=59.7
Sample size = n = 72.
Part a) What is the critical value for this test?
significance level of α=0.001
Since this is right tailed test, look in z table for
Area = 1 - 0.001 = 0.9990 or its closest area and find z value.
Area 0.9990 corresponds to 3.0 and 0.09
thuz z critical value = 3.09
z critical = 3.090
Part b) What is the test statistic for this sample?
Part c) The test statistic is...?
The test statistic is = 2.957 < z critical value = 3.090, hence the test statistic is not in the critical region.
Part d) This test statistic leads to a decision to fail to reject the null.
Part e) As such, the final conclusion is that:
There is not sufficient sample evidence to support the claim that the population mean is greater than 57.4.