In: Statistics and Probability
It is desired to develop a means chart and a range chart for a process that puts a cola drink | |||||
into bottles. The nominal goal is to put 16 oz. into each bottle. The data were obtained from 25 of size 4 | |||||
A. Construct means and range charge obtained information and 3-sigma limits. | |||||
B. Then graph the data on the chart. Identify any samples that indicate the process is out of | |||||
control. | |||||
Pop into Bottles Problem | |||||
Sample number | Item 1 | Item 2 | Item 3 | Item 4 | |
1 | 16.01783 | 16.00249 | 16.00451 | 15.94237 | |
2 | 15.98764 | 16.00713 | 15.97385 | 16.00362 | |
3 | 16.00253 | 16.00251 | 15.97343 | 15.98449 | |
4 | 16.01994 | 16.00793 | 16.00592 | 15.97239 | |
5 | 15.99596 | 16.00336 | 16.00137 | 15.98503 | |
6 | 15.9938 | 15.99357 | 16.00254 | 15.98667 | |
7 | 15.98799 | 15.99871 | 15.97896 | 15.95939 | |
8 | 16.01234 | 16.00982 | 15.98147 | 15.9929 | |
9 | 16.00267 | 15.99257 | 15.98403 | 15.99413 | |
10 | 16.01079 | 16.00738 | 16.00969 | 15.95743 | |
11 | 16.0093 | 16.00942 | 15.97481 | 16.00514 | |
12 | 15.99942 | 16.00028 | 15.97622 | 15.9607 | |
13 | 15.98469 | 16.00018 | 15.99772 | 15.95608 | |
14 | 16.01878 | 15.99014 | 15.97092 | 15.95334 | |
15 | 16.00395 | 15.9985 | 16.00445 | 15.95483 | |
16 | 16.00048 | 15.99394 | 15.97393 | 15.96496 | |
17 | 16.00953 | 15.99736 | 16.00449 | 15.9914 | |
18 | 15.99745 | 15.99101 | 15.9846 | 16.00898 | |
19 | 16.01559 | 16.00196 | 15.9869 | 15.96941 | |
20 | 16.01938 | 16.00702 | 15.98757 | 16.00441 | |
21 | 15.98027 | 15.99967 | 15.97739 | 15.96144 | |
22 | 16.0127 | 16.00559 | 15.97053 | 15.96983 | |
23 | 16.00743 | 16.00365 | 15.97541 | 15.97034 | |
24 | 15.98654 | 16.00141 | 16.00254 | 15.96317 | |
25 | 16.00996 | 15.99368 | 15.97339 | 15.94784 | |
The solution to both the parts is given below:
A X bar R chart will be made in this regard...
The Grand Mean and the Overall Range is calculated below:
Grand Mean is just the overall average of the group means and the Overall Range is the average of the group range.
Range = Maximum Value - Minimum Value
Formulas:
Table for A2
In this case A2 will be 0.729 as the sample size is 4.
So,
From X bar R Chart formulas,
LCL = 15.99 - 0.729*0.0388 = 15.962 (Lower Control Limit)
UCL = 15.99 + 0.729*0.0388 = 16.02 (Upper Control Limit)
Based on 3 Sigma limit:
LCL = 15.99 - 3*0.0388 = 15.874 (Lower Control Limit)
UCL = 15.99 + 3*0.0388 = 16.11 (Upper Control Limit)
Control Chart
Here, the two black lines denotes the LCL (Lower Control Limit) and the UCL (Upper Control Limit)
Here as all the points are under the control limits, so the process is under control...
End of the Solution...