. A random variable has a X^2 2 distribution with 9 degrees of freedom. What is...

. A random variable has a X^2 2 distribution with 9 degrees of freedom. What is the probability that the random variable will be between 16.919 and 21.666? Explain your work

Expert Solution

(A)First of all, open the chi square distribution table critical values.

(B)find the column corresponding to degree of freedom = 9

(C)locate 16.919 and 21.666 in the row corresponding to df value of 9

{In chi-square distribution table, you will find 16.92 and 21.67 only}

(D) Now, look for the alpha levels or significance levels corresponding to 16.919 and 21.666 in their respective columns.

you will find significance level 0.05 corresponding to 16.919 and 0.01 corresponding to 21.666

So, the required p value will be within 0.01 and 0.05

orchestra answered 2 years ago

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