Let X be a random variable with an N(2,4) distribution. FindP(|X−2|^2 >.36)

Expert Solution

µ = 2

sd = sqrt(4) = 2

P(|X - 2|² > 0.36) = P(|X - 2| > 0.6)

= 1 - P(|X - 2| < 0.6)

= 1 - P(|(X - µ) / sd| < 0.6/sd)

= 1 - P(|Z| < 0.6/2)

= 1 - P(-0.3 < Z < 0.3)

= 1 - (P(Z < 0.3) - P(Z < -0.3))

= 1 - (0.6179 - 0.3821)

= 0.7642

orchestra answered 2 years ago

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Question

Let X be a random variable with an N(2,4) distribution. FindP(|X−2|^2 >.36)

Solutions

Expert Solution

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