Volume1=5.0L, Temperature= 35.0+ 273K, which exands to 7.4L, pressure remaining the same. What is the new...

Volume1=5.0L, Temperature= 35.0+ 273K, which exands to 7.4L, pressure remaining the same. What is the new temperature.?

Expert Solution

Initial Final

V1 = 5L V2 = 7.4L

T1 = 308K T2 =

V1/T1 = V2/T2

T2 = V2T1/V1

= 7.4*308/5 = 455.84K

The new temperature = 455.84K = 455.84-273 = 182.84⁰ C

queen_honey_blossom answered 1 year ago

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