Question

In: Statistics and Probability

Use the given information to find the number of degrees of​ freedom, the critical values chi...

Use the given information to find the number of degrees of​ freedom, the critical values chi Subscript Upper L Superscript 2 and chi Subscript Upper R Superscript 2​, and the confidence interval estimate of sigma. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Nicotine in menthol cigarettes 90​% ​confidence; nequals23​, sequals0.24 mg.

Solutions

Expert Solution

Solution :

Given that,

n = 23

df = 23 - 1 = 22

s = 0.24

s2 = 0.0576

2L = 2/2,df = 33.924

2R = 21 - /2,df = 12.338

The 90% confidence interval for is,

(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2

  22 * 0.0576 / 33.924 < < 22 * 0.0576 / 12.338

0.19 < < 0.32

(0.19 , 0.32)


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