Question
In: Statistics and Probability
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of freedom, the critical values chi Subscript Upper L Superscript 2 and chi Subscript Upper R Superscript 2, and the confidence interval estimate of sigma. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution. Nicotine in menthol cigarettes 90% confidence; nequals23, sequals0.24 mg.
Solutions
Expert Solution
Solution :
Given that,
n = 23
df = 23 - 1 = 22
s = 0.24
s2 = 0.0576
2L
=
2
/2,df
= 33.924
2R
=
21 -
/2,df = 12.338
The 90% confidence interval for 
is,
(n
- 1)s2 /
2/2
<
<
(n - 1)s2 /
21 -
/2
22
* 0.0576 / 33.924 <
<
22 * 0.0576 / 12.338
0.19 <
< 0.32
(0.19 , 0.32)
orchestra answered 3 years agoRelated Solutions
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 90% confidence;
nequals24, sequals65.4.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 90% confidence;
n=22, s=65.8.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values
chi Subscript Upper L Superscript 2χ2L
and
chi Subscript Upper R Superscript 2χ2R,
and the confidence interval estimate of
sigmaσ.
It is reasonable to assume that a simple random sample has been
selected from a population with a normal distribution.
Platelet Counts of Women
9898%
confidence;
nequals=2424,
sequals=65.165.1.
LOADING...
Click the icon to view the table of Chi-Square critical
values.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 99% confidence;
nequals26, sequals65.1.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 90% confidence;
n=23, s=65.2.
Can you please simplify the solution so i can do the rest on my
own.
Thank you!
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values
chi Subscript Upper L Superscript 2χ2L and chi Subscript Upper R
Superscript 2χ2R, and the confidence interval estimate of
sigmaσ.
It is reasonable to assume that a simple random sample has been
selected from a population with a normal distribution.
Nicotine in menthol cigarettes 90% confidence; n=24,
s=0.27mg.
I need help finding the XL^2 , XR^2, and the confidence interval
estimate of sigma is _...
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Nicotine in menthol cigarettes 90%
confidence; nequals23, sequals0.25 mg.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values chi Subscript Upper L Superscript 2
and chi Subscript Upper R Superscript 2, and the confidence
interval estimate of sigma. It is reasonable to assume that a
simple random sample has been selected from a population with a
normal distribution. Platelet Counts of Women 95% confidence;
nequals22, sequals65.6.
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values
chi Subscript Upper L Superscript 2χ2L
and
chi Subscript Upper R Superscript 2χ2R,
and the confidence interval estimate of
sigmaσ.
It is reasonable to assume that a simple random sample has been
selected from a population with a normal distribution.Nicotine in
menthol cigarettes
9595%
confidence;
nequals=2727,
sequals=0.240.24
mg.
LOADING...
Click the icon to view the table of Chi-Square critical
values.
dfequals=nothing
(Type a whole number.)...
Use the given information to find the number of degrees of freedom, the critical values chi...
Use the given information to find the number of degrees of
freedom, the critical values
chi Subscript Upper L Superscript χ2L
and
chi Subscript Upper R Superscript χ2R,
and the confidence interval estimate of
sigmaσ.
It is reasonable to assume that a simple random sample has been
selected from a population with a normal distribution.
Platelet Counts of Women
95%
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s=65.4.
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