Question

Use the given information to find the number of degrees of​ freedom, the critical values

chi Subscript Upper L Superscript 2χ2L

and

chi Subscript Upper R Superscript 2χ2R​,

and the confidence interval estimate of

sigmaσ.

It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution.Nicotine in menthol cigarettes

9595​%

​confidence;

nequals=2727​,

sequals=0.240.24

mg.

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Click the icon to view the table of​ Chi-Square critical values.

dfequals=nothing

​(Type a whole​ number.)

chi Subscript Upper L Superscript 2χ2Lequals=nothing

​(Round to three decimal places as​ needed.)

chi Subscript Upper R Superscript 2χ2Requals=nothing

​(Round to three decimal places as​ needed.)The confidence interval estimate of

sigmaσ

is

nothing

mgless than<sigmaσless than<nothing

mg.

​(Round to two decimal places as​ needed.)

Answer 1

Solution :

Given that,

s = 0.24

s² = 0.0576

²_L = ²_/2,df = 41.923

²_R = ²_{1 - /2,df} = 13.844

The 95% confidence interval for is,

(n - 1)s² / ²_/2 < < (n - 1)s² / ²_{1 - /2}

  26 * 0.0576 / 41.923 < < 26 * 0.0576 / 13.844

0.19 < < 0.33