In: Statistics and Probability
Use the given information to find the number of degrees of freedom, the critical values
chi Subscript Upper L Superscript 2χ2L
and
chi Subscript Upper R Superscript 2χ2R,
and the confidence interval estimate of
sigmaσ.
It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution.
Platelet Counts of Women
9898%
confidence;
nequals=2424,
sequals=65.165.1.
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Solution :
Given that,
s = 65.1
s2 = 4238.01
2L = 2/2,df = 41.638
2R = 21 - /2,df = 10.196
The 98% confidence interval for is,
(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2
23 * 4238.01 / 41.638 < < 23 * 4238.01 / 10.196
48.38 < < 97.78
(48.38 , 97.78)