In: Statistics and Probability
a ) Find the margin of error for the given values of c, s, and n. c = 0.80, s = 6, n = 15;
b ) Find the margin of error for the given values of c, s, and n. c = 0.98 s =2.1, n =10;
c) Construct the indicated confidence interval for the population mean muμusing the t-distribution. Assume the population is normally distributed.c =0.90 x =14.9 s =3.0 n =10 The 90% confidence interval using a t-distribution is
d) Construct the indicated confidence interval for the population mean muμusing a t-distribution. c =0.98, x = 109 s =10, n =7
Part a_
Margin of Error =
Margin of Error =
Margin of Error = 2.084
Part b)
Margin of Error =
Margin of Error =
Margin of Error = 1.874
Part c)
Confidence Interval
Lower Limit =
Lower Limit = 13.161
Upper Limit =
Upper Limit = 16.639
90% Confidence interval is ( 13.161 , 16.639 )
Part d)
Confidence Interval
Lower Limit =
Lower Limit = 97.1218
Upper Limit =
Upper Limit = 120.8782
98% Confidence interval is ( 97.1218 , 120.8782 )