(a) find the margin of error for the values of c, s, and n, and (b)...

(a) find the margin of error for the values of c, s, and n, and (b) construct the confidence interval for m using the t-distribution. Assume the population is normally distributed.

16. c = 0.99, s = 16.5, n = 20, x = 25.2

Solutions

Expert Solution

Solution :

Given that,

=25.2

s = 16.5

n = 20

Degrees of freedom = df = n - 1 = 20 - 1 = 19

A ) At 99% confidence level the t is ,

= 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

t_/2,df = t_0.005,19 = 2.861

Margin of error = E = t_/2,df * (s / $\sqrt$ n)

= 2.861 * (16.5 / $\sqrt$ 20)

= 10.55

Margin of error = 10.55

B )The 99% confidence interval estimate of the population mean is,

- E < < + E

25.20 - 10.55 < < 25.2 + 10.55

14.65 < < 35.75

orchestra answered 1 year ago

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