Question

In: Statistics and Probability

A particular lake is known to be one of the best places to catch a certain...

A particular lake is known to be one of the best places to catch a certain type of fish. In this table, x = number of fish caught in a 6-hour period. The percentage data are the percentages of fishermen who caught x fish in a 6-hour period while fishing from shore. x 0 1 2 3 4 or more % 43% 35% 15% 6% 1% (a) Convert the percentages to probabilities and make a histogram of the probability distribution. (Select the correct graph.) (b) Find the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period. (Enter a number. Round your answer to two decimal places.) (c) Find the probability that a fisherman selected at random fishing from shore catches two or more fish in a 6-hour period. (Enter a number. Round your answer to two decimal places.) (d) Compute μ, the expected value of the number of fish caught per fisherman in a 6-hour period (round 4 or more to 4). (Enter a number. Round your answer to two decimal places.) μ = fish (e) Compute σ, the standard deviation of the number of fish caught per fisherman in a 6-hour period (round 4 or more to 4). (Enter a number. Round your answer to three decimal places.) σ = fish

Solutions

Expert Solution

SOLUTION:

From given data,

(a) Convert the percentages to probabilities and make a histogram of the probability distribution.

(b) Find the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period.

the probability that a fisherman selected at random fishing from shore catches one or more fish in a 6-hour period.

= 0.35+0.15+0.06+0.01 =0.57

(c) Find the probability that a fisherman selected at random fishing from shore catches two or more fish in a 6-hour period.

the probability that a fisherman selected at random fishing from shore catches two or more fish in a 6-hour period.

= 0.15+0.06+0.01 =0.22

(d) Compute μ, the expected value of the number of fish caught per fisherman in a 6-hour period (round 4 or more to 4). (Enter a number. Round your answer to two decimal places.) μ = fish

We simplify the value of

x=4 or more as x=4

Hence,

X Probability (p) P*X X2 P*X2
0 0.43 0 0 0
1 0.35 0.35 1 0.35
2 0.15 0.3 4 0.6
3 0.06 0.18 9 0.54
4 0.01 0.04 16 0.16
Total 1 0.87 1.65

Expected value =

(e) Compute σ, the standard deviation of the number of fish caught per fisherman in a 6-hour period (round 4 or more to 4). (Enter a number. Round your answer to three decimal places.) σ = fish

Standard deviation =

=


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