Question

Each year a certain magazine publishes a list of "Best Places to Live in the United States." These listings are based on affordability, educational performance, convenience, safety, and livability. Suppose the list below shows the median household income of the magazine's top city in each U.S. state for a certain year. (Round your answers to the nearest cent.)

City	Median Household Income ($)	City	Median Household Income ($)
Pelham, AL	66,770	Bozeman, MT	49,301
Juneau, AK	84,099	Papillion, NE	79,129
Paradise Valley, AZ	138,190	Sparks, NV	54,228
Fayetteville, AR	40,833	Nashua, NH	66,870
Monterey Park, CA	57,417	North Arlington, NJ	73,883
Lone Tree, CO	116,759	Rio Rancho, NM	58,980
Manchester, CT	64,826	Valley Stream, NY	88,691
Hockessin, DE	115,122	Concord, NC	54,577
St. Augustine, FL	47,746	Dickinson, ND	71,864
Vinings, GA	73,101	Wooster, OH	43,052
Kapaa, HI	62,544	Mustang, OK	66,712
Meridian, ID	62,897	Beaverton, OR	58,783
Schaumburg, IL	73,822	Lower Merion, PA	117,436
Fishers, IN	87,041	Warwick, RI	63,412
Council Bluffs, IA	46,842	Mauldin, SC	57,478
Lenexa, KS	76,503	Rapid City, SD	47,786
Georgetown, KY	58,707	Franklin, TN	82,332
Bossier City, LA	47,049	Allen, TX	104,522
South Portland, ME	56,470	Orem, UT	54,513
Rockville, MD	100,156	Colchester, VT	69,179
Waltham, MA	75,104	Reston, VA	112,720
Farmington Hills, MI	71,152	Mercer Island, WA	128,482
Woodbury, MN	99,655	Morgantown, WV	38,058
Olive Branch, MS	62,956	New Berlin, WI	74,981
St. Peters, MO	57,726	Cheyenne, WY	56,591

(a)

Compute the mean and median (in $) for these household income data.

mean$ _______________

median$ ________________

(c)

Compute the range and standard deviation (in $) for these household income data. (Round your standard deviation to the nearest cent.)

range$ _____________

standard deviation$ ________________

(d)

Compute the first and third quartiles (in $) for these household income data.

Q₁$ ____________________

Q₃$ ____________________

(e)

Are there any outliers in these data?

There  ---Select--- below the lower limit and  ---Select--- above the upper limit.

What does this suggest about the data?

There are no outliers in the data, which is likely why the mean value is the same as the median.

There are no outliers in the data, which is likely why the mean value is greater than the median.    

There are outliers in the data, which is likely why the mean value is less than the median.

There are no outliers in the data, which is likely why the mean value is less than the median.

There are outliers in the data, which is likely why the mean value is greater than the median.

Answer 1

There are outliers in the data, which is likely why the mean value is greater than the median.

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