Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2...

Container 1 has 8 items, 3 of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from each container, what is the probability that only one of the items is defective?

Expert Solution

Probability = 3/8 * 3/5 + 5/8 * 2/5 = 0.475

orchestra answered 2 years ago

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