In: Statistics and Probability
A box contains 12 items of which 3 are defective. A sample of 3 items is selected from the box. Let X denotes the number of defective item in the sample. Find the probability distribution of X.
Probability of being deefective=3/12=1/4=0.25
sample size,n=3
X=number of defective items in the sample
We can use binomial distribution for X,as probability of success is constant for each trial and trails are independent.
P(x=r)=3Cr*0.25r*(1-0.25)3-r
| x | p(x) |
| 0 | 0.4219 |
| 1 | 0.4219 |
| 2 | 0.1406 |
| 3 | 0.0156 |