Container 1 has 8 items,3of which are defective. Container 2 has 5 items, 2 of which...

Container 1 has 8 items,3of which are defective. Container 2 has 5 items, 2 of which are defective. If one item is drawn from each container, what is the probability that only one of the items is defective?

0.2250

0.3000

0.0250

0.4750

0.1500

Expert Solution

P(Only one item is defective)

= P(Defective from 1 and good from 2) + P(Defective from 2 and good from 1)

= (3/8)*(3/5) + (5/8)*(2/5)

= 19/40

= 0.4750

Option D is correct.

orchestra answered 2 years ago

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