A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The...

A vertical curve has an incoming grade of +4.4% and an exit grade of -2.2%. The length of the curve is 450.00 ft. The intersection of the grades is at 10+00 and the elevation at that point is 440.00. Compute the elevation of the +00 points on the curve. Then determine the location and elevation of the highest point on the curve. If there is an existing bridge at this location over the proposed road, and the elevation of its lowest point is 451.00 and the required clearance is a minimum of 14.0 ft, does this curve need to be re-designed, or will it fit the required parameter?

PLZ break into steps

Expert Solution

Ally Wells answered 11 months ago

A vertical curve has an incoming grade of -3.2% and the exit grade is +2.2%. The...

A vertical curve has an incoming grade of -3.2% and the exit grade is +2.2%. The length of the curve is 800 ft. The stationing and elevation at the point of intersection of the grades are 73+22 and 1842.35 ft. Compute the curve and determine elevations on the curve at the +00 points. Then determine the elevation of the curve at the low point. If a sewer pipe is to pass underneath at the lowest point, what elevation should the...

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents...

A 1000-ft vertical curve connects a -1% grade to a -3.5% grade. If the vertical tangents intersect at sta. 38+60.24 and elevation 1,400.13 ft, develop an Excel spreadsheet to calculate the elevations of the grade line at each station from sta. 31+00 to 45+00. Include the elevations of the PVC and PVT.

A vertical curve is designed for 90 km/h and has an initial grade of + 2.5%...

A vertical curve is designed for 90 km/h and has an initial grade of + 2.5% and a final grade of -1.0%. The PVT is at station 3 + 480. It is known that a point on the curve at station 3 + 440 is at elevation 75 m. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?

A vertical curve is designed for 75 km/h and has an initial grade of + 3.5%...

A vertical curve is designed for 75 km/h and has an initial grade of + 3.5% and a final grade of -2.0%. The PVT is at station 3 + 560. It is known that a point on the curve at station 3 + 520 is at elevation 85 m. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?

A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and...

A vertical curve is designed for 55 mi/h and has an initial grade of +2.5% and a final grade of −1.0%. The PVT is at station 114 + 50. It is known that a point on the curve at station 112 + 35 is at elevation 245 ft. What is the stationing and elevation of the PVC? What is the stationing and elevation of the high point on the curve?

A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%....

A sag vertical curve is to join a grade of g1=−3.50% to a grade of g2=−1.25%. What is the minimum length of the curve for acceptable passing sight distance at night, with headlight illumination? Express your answer in feet to five significant figures. there is no more info. this is all that was given to us.

An equal-tangent crest vertical curve connects an initial grade of +2.5% and a final grade of...

An equal-tangent crest vertical curve connects an initial grade of +2.5% and a final grade of –0.5%. The curve is designed for 70 mi/h and the station of the PVT is 132+62 and is at elevation 833 ft. What is the station and elevation of the curve's high point?

A vertical curve of 1000 feet is designed to connect a grade of +4% to a...

A vertical curve of 1000 feet is designed to connect a grade of +4% to a grade of -5%. The PVI is located at station 1500+55 and has a know elevation of 500 feet. Find the following: The station and elevation of the PVC The station and elevation of the PVT The elevation of points along the vertical curve at 100-feet intervals The location and elevation of the high point on the curve

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of...

A vertical curve has its PVI at station 14+75.00 and elevation 76.29 ft. The grade of the back tangent is 3.4%, the grade of the forward tangent is -4.8%, and the curve length is 450 ft. Determine the stations and elevations of the BVC and EVC. Determine the location and elevation of the high point of the curve. Determine the curve elevation at station 14+00 and station 16+00.

An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and...

An equal-tangent crest vertical curve is designed for 100 km/h. The initial grade is +3.4% and the final grade is negative. Draw the curve. What is the elevation difference between the PVC and the high point of the curve?

Question