In: Statistics and Probability
A club with 23 members is voting on a proposal. A group of 5 has decided to vote in favor of the proposal while each of the rest of the members vote independently with a chance of 44% in favor of the proposal. What are the chances that the proposal will get the majority vote.
Of the 23 members, 5 will vote in favor of the proposal
From the remaining n = 18, each will vote in favor with probability, p = 0.44
q = 1 - p = 0.56
P(the proposal will get the majority vote) = P(number of total votes in favor 12)
= P(number of votes in favor from the remaining 18 7)
np = 18x0.44 = 7.92
nq = 18x0.56 = 10.08
Normal approximation for binomial can be used here since both np and nq 5
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np = 7.92
Standard deviation =
=
= 2.106
P(the proposal will get majority vote) = P(X 7)
= 1 - P(X < 6.5) (with continuity correction)
= 1 - P(Z < (6.5 - 7.92)/2.016)
= 1 - P(Z < -0.67)
= 1 - 0.2502
= 0.7498
(Approximately 75%)