Question

In: Statistics and Probability

An environmentalist wants to determine the relationship between the number of fires, in thousands, and the number of acres burned, in hundreds of thousands.

 

An environmentalist wants to determine the relationship between the number of fires, in thousands, and the number of acres burned, in hundreds of thousands. Based on this data, decide if the correlation is significant at alpha = 0.05.

Number of fires x 73 74 58 48 80 65 54 49
Number of acres burned y 64 46 22 23 51 12 29 10

1. Draw a scatter plot of the data.

2. Showing all work calculate r.

3. Showing all work determine where to reject or not reject the null hypothesis.

4. Determine the line of best fit y = a + bx.

5. When x = 61 what is y and what does it mean I this context.

6. Determine r^2.

7. Determine Sset.

8. Find the 95% prediction interval when x = 61.

Solutions

Expert Solution

1)

2. Showing all work calculate r.

X Y X*Y X2 Y2
73 64 4672 5329 4096
74 46 3404 5476 2116
58 22 1276 3364 484
48 23 1104 2304 529
80 51 4080 6400 2601
65 12 780 4225 144
54 29 1566 2916 841
49 10 490 2401 100
Sum = 501 257 17372 32415 10911

3. Showing all work determine where to reject or not reject the null hypothesis.

The hypothesis being tested is:

H0: β1 = 0

H1: β1 ≠ 0

ANOVA table
Source SS   df   MS F p-value
Regression 1,569.1183 1   1,569.1183 8.67 .0258
Residual 1,085.7567 6   180.9595
Total 2,654.8750 7  

Since p value

There is sufficient evidence to conclude that β1 not equal to zero at 5% level of significance.

4. Determine the line of best fit y = a + bx.

5. When x = 61 what is y and what does it mean I this context.

This means that when number of fires is 61 then the predicted value of the number of acres burned is 30.1293 n hundreds of thousands.

6. Determine r^2.

r=0.769

r^2=0.769^2=0.5914

7. Determine Sset=13.452

Using excel

Regression Analysis
0.591
r   0.769
Std. Error   13.452
n   8
k   1
Dep. Var. Number of acres burned,y
ANOVA table
Source SS   df   MS F p-value
Regression 1,569.1183 1   1,569.1183 8.67 .0258
Residual 1,085.7567 6   180.9595
Total 2,654.8750 7  
Regression output confidence interval
variables coefficients std. error    t (df=6) p-value 95% lower 95% upper
Intercept -44.8031 26.55 -1.69 0.14 -109.78 20.17
Number of fires,x 1.2284 0.4172 2.945 .0258 0.2076 2.2491
Predicted values for: Number of acres burned,y
95% Confidence Interval 95% Prediction Interval
Number of fires,x Predicted lower upper lower upper Leverage
61 30.129 18.374 41.884 -4.823 65.081 0.128

8. Find the 95% prediction interval when x = 61.


The 95% prediction interval is (-4.823,65.081)


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