In: Statistics and Probability
An environmentalist wants to determine the relationship between the number of fires, in thousands, and the number of acres burned, in hundreds of thousands. Based on this data, decide if the correlation is significant at alpha = 0.05.
Number of fires x | 73 | 74 | 58 | 48 | 80 | 65 | 54 | 49 |
Number of acres burned y | 64 | 46 | 22 | 23 | 51 | 12 | 29 | 10 |
1. Draw a scatter plot of the data.
2. Showing all work calculate r.
3. Showing all work determine where to reject or not reject the null hypothesis.
4. Determine the line of best fit y = a + bx.
5. When x = 61 what is y and what does it mean I this context.
6. Determine r^2.
7. Determine Sset.
8. Find the 95% prediction interval when x = 61.
1)
2. Showing all work calculate r.
X | Y | X*Y | X2 | Y2 | |
73 | 64 | 4672 | 5329 | 4096 | |
74 | 46 | 3404 | 5476 | 2116 | |
58 | 22 | 1276 | 3364 | 484 | |
48 | 23 | 1104 | 2304 | 529 | |
80 | 51 | 4080 | 6400 | 2601 | |
65 | 12 | 780 | 4225 | 144 | |
54 | 29 | 1566 | 2916 | 841 | |
49 | 10 | 490 | 2401 | 100 | |
Sum = | 501 | 257 | 17372 | 32415 | 10911 |
3. Showing all work determine where to reject or not reject the null hypothesis.
The hypothesis being tested is:
H0: β1 = 0
H1: β1 ≠ 0
ANOVA table | |||||
Source | SS | df | MS | F | p-value |
Regression | 1,569.1183 | 1 | 1,569.1183 | 8.67 | .0258 |
Residual | 1,085.7567 | 6 | 180.9595 | ||
Total | 2,654.8750 | 7 |
Since p value There is sufficient evidence to conclude that β1 not
equal to zero at 5% level of significance. 4. Determine the line of best fit y = a + bx. 5. When x = 61 what is y and what does it mean I this
context. This means that when number of fires is 61 then the predicted
value of the number of acres burned is 30.1293 n hundreds of
thousands. 6. Determine r^2. r=0.769 r^2=0.769^2=0.5914 7. Determine Sset=13.452 Using excel
8. Find the 95% prediction interval when x = 61.
Regression Analysis
r²
0.591
r
0.769
Std. Error
13.452
n
8
k
1
Dep. Var.
Number of acres
burned,y
ANOVA table
Source
SS
df
MS
F
p-value
Regression
1,569.1183
1
1,569.1183
8.67
.0258
Residual
1,085.7567
6
180.9595
Total
2,654.8750
7
Regression output
confidence
interval
variables
coefficients
std. error
t
(df=6)
p-value
95% lower
95% upper
Intercept
-44.8031
26.55
-1.69
0.14
-109.78
20.17
Number of fires,x
1.2284
0.4172
2.945
.0258
0.2076
2.2491
Predicted values for: Number of acres
burned,y
95% Confidence
Interval
95% Prediction
Interval
Number of fires,x
Predicted
lower
upper
lower
upper
Leverage
61
30.129
18.374
41.884
-4.823
65.081
0.128
The 95% prediction interval is (-4.823,65.081)