In: Chemistry
How many grams of NaOH (MW = 40.0) are there in 500.0 mL of a 0.175 M NaOH solution?
Given Molarity of NaOH solution , M = 0.175 M
Volume of the solution , V = 500.0 mL
= 500.0mL x ( 1/1000) (L/mL)
= 0.5 L
We know that Molarity , M = number of moles of NaOH / volume of solution in L
From this number of moles of NaOH , n = Molarity x volume in L
= 0.175 M x 0.5 L
= 0.0875 mol
Number of moles , n = mass/ molar mass
So mass of NaOH present , m = number of moles x molar mass
= 0.0875 mol x 40.0 (g/mol)
= 3.5 g
Therefore the mass of NaOH is 3.5g