In: Statistics and Probability
Suppose a sample of 2339 tenth graders is drawn. Of the students sampled, 1942 read above the eighth grade level. Using the data, construct the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
We have given,
x=2339-1942=397
n=2339
Estimate for sample proportion=
0.1697
Level of significance is =1-0.99=0.01
Z critical value(using Z table)=2.576
Confidence interval formula is
=(0.1497,0.1897
Lower limit for confidence interval=0.150
Upper limit for confidence interval=0.190