In: Math
Suppose a sample of 1042 tenth graders is drawn. Of the students sampled, 865 read above the eighth grade level. Using the data, construct the 90% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.
I need help figuring out the formula for this problem.
We have given,
x=1042-865=177
n=1042
Estimate for sample proportion=
0.1699
Level of significance is =1-0.90=0.1
Z critical value(using Z table)=1.645
Confidence interval formula is
=(0.151,0.189)
Lower limit for confidence interval=0.151
Upper limit for confidence interval=0.189