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Suppose a sample of 1042 tenth graders is drawn. Of the students sampled, 865 read above...

Suppose a sample of 1042 tenth graders is drawn. Of the students sampled, 865 read above the eighth grade level. Using the data, construct the 90% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level. Round your answers to three decimal places.

I need help figuring out the formula for this problem.

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Expert Solution

We have given,              
              
x=1042-865=177          
n=1042          
Estimate for sample proportion=   0.1699  
Level of significance is =1-0.90=0.1      
Z critical value(using Z table)=1.645      
              
Confidence interval formula is              


=(0.151,0.189)     

       
Lower limit for confidence interval=0.151  
              
Upper limit for confidence interval=0.189  
              


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