In: Civil Engineering
Given:
- Level terrain - extended freeway segment
- Urban area with 0.9 interchanges/km
- DDHV 4050 vehicles/hour
- 10% trucks, no buses, no RVs
- PHF 0.95
- Full shoulder and 3.6m wide lanes
Determine:
- Number of lanes to operate at LOS=C
Assume Base free flow speed (BFFS) = 90 kmph
Lane width = 3.6 m
Reduction in speed corresponding to lane width, fLW = 0 kmph
Lateral Clearance = 1.8 m
Reduction in speed corresponding to lateral clearance, fLC kmph
Interchanges/Ramps = 0.9/km
Reduction in speed corresponding to Interchanges/ramps, fID = 8.1 kmph
No. of lanes in one direction = n
Reduction in speed corresponding to number of lanes, fN kmph
Free Flow Speed (FFS) = BFFS – fLW – fLC – fN – fID= 90 – 0 - 8.1 - fLC – fN kmph
Peak Flow, V = 4050 veh/hr
Peak-hour factor = 0.95
Trucks = 10 %
Level Terrain
fHV = 1/ (1 + 0.10 (1.5-1)) = 1/1.05 = 0.952
fP = 1.0
Peak Flow Rate, Vp = V / (PHV*n*fHV*fP) = 4050/ (0.95*n*0.952*1.0) = 4478.11/n ~ 4478/n veh/hr/ln
S = FFS
Density = Vp/S
Hence Level of Service is C
Density of LOS C should lie between 11 – 16 veh/km/ln
a) Assume 2 - lanes in each direction
FFS = 81.9 - 7.3 - 0 = 74.6 kmph
Flow rate = 4478/2 = 2239 veh/hr/ln
Density = 2239/74.6 = 30.03 veh/km/ln
Not possible
b) Assume 3 - lanes in each direction
FFS = 81.9 - 4.8 - 0 = 77.1 kmph
Flow rate = 4478/3 = 1493 veh/hr/ln
Density = 1493/77.1 = 19.36 veh/km/ln
Not possible
C) Assume 4 - lanes in each direction
FFS = 81.9 - 2.4 - 0 = 79.5 kmph
Flow rate = 4478/4 = 1120 veh/hr/ln
Density = 1120/79.5 = 14.08 veh/km/ln
Possible
Hence, Four- lanes in each direction should be considered to obtain LOS C
Total number of lanes = 8