In: Civil Engineering
The extract below is taken from a Level Book for levels taken between 2 TBMs. Complete the Level Book entries as well as calculate the adjusted RL (reduced levels) for all entries. The misclose error can be assumed acceptable. Note: all staff readings are in meters.
BS | IS | FS | Rise | Fall | RL | Correction | Corrected RL | Notes |
1.379 | TBM RL 175.5 | |||||||
2.795 | PEG 1 | |||||||
3.215 | PEG 2 | |||||||
0.595 | PEG 3 | |||||||
1.270 | PEG 4 | |||||||
1.280 | 3.215 | CP B | ||||||
1.030 | PEG 5 | |||||||
3.045 | PEG 6 | |||||||
2.312 | 3.815 | CP C | ||||||
1.743 | 3.227 | CP D | ||||||
2.735 | PEG 7 | |||||||
3.623 | TBM RL 168.50 |
BS | IS | FS | RISE | FALL | RL |
1.379 | 175.5 | ||||
2.795 | 1.416 | 174.084 | |||
3.215 | 0.42 | 173.664 | |||
0.595 | 2.62 | 176.284 | |||
1.27 | 0.675 | 175.609 | |||
1.28 | 3.215 | 1.945 | 173.664 | ||
1.03 | 0.25 | 173.914 | |||
3.045 | 2.015 | 171.899 | |||
2.312 | 3.815 | 0.77 | 171.129 | ||
1.743 | 3.227 | 0.915 | 170.214 | ||
2.735 | 0.992 | 169.222 | |||
3.623 | 0.888 | 168.334 | |||
6.714 | 13.88 | 2.87 | 10.036 |
[Note:
Rise or Fall in any row = BS or IS of previous row - IS or FS of the considered row.
If the obtained value is positive, then write it in rise column.
If the obtained value is negative, then write it in fall column.
For example:
In second row: BS of first row - IS of second row = 1.379 - 2.795 = - 1.416
Obtained value is negative, hence written in fall column.
Similarly in 4th row: IS of 3rd row - IS of 4th row = 3.215 - 0.595 = + 2.62
Obtained value is positive, hence written in rise column.
RL in any row = RL in previous row + Rise in the row ( if rise is present in the row considered)
= RL of previous row - Fall in the row (If fall is present in the row considered) ]
Check:
i)
From the above table we have,
Sum of back sights = 6.714
Sum of fore sights = 13.88
Therefore,
Sum of back sights - Sum of fore sights = 6.714 - 13.88 = -7.166
ii)
Sum of rises = 2.87
Sum of falls = 10.036
Therefore,
Sum of rise - Sum of falls = 2.87 - 10.036 = -7.166
iii)
Last RL = 168.334
First RL = 175.50
Therefore,
Last RL - First RL = 168.334 - 175.50 = -7.166
Therefore we can say that,
Sum of back sights - Sum of fore sights = Sum of rise - Sum of falls = Last RL - First RL
Hence calculations performed are correct.
Error of misclosure (e):
Obtained value of last RL = 168.334
But given that, correct value of last RL = 168.50
Therefore error of misclosure (e) = Obtained RL - Correct RL
= 168.334 - 168.50
Therefore, error of misclosure (e) = -0.166
Correction:
As the error is negative, correction must be positive.
Therefore, total correction = + 0.166
Total number of set up of instruments = 4 (Number of instrument set up = Number of back sights available)
Therefore correction per set up = Total correction / Number of setup
= + 0.166 / 4
= + 0.0415
BS | IS | FS | RISE | FALL | RL | CORRECTION | CORRECTED RL | Notes |
1.379 | 175.5 | - | 175.5 | TBM 1 | ||||
2.795 | 1.416 | 174.084 | 0.0415 | 174.1255 | PEG1 | |||
3.215 | 0.42 | 173.664 | 0.0415 | 173.7055 | PEG2 | |||
0.595 | 2.62 | 176.284 | 0.0415 | 176.3255 | PEG3 | |||
1.27 | 0.675 | 175.609 | 0.0415 | 175.6505 | PEG4 | |||
1.28 | 3.215 | 1.945 | 173.664 | 0.0415*2 = 0.083 | 173.747 | CP 1 | ||
1.03 | 0.25 | 173.914 | 0.083 | 173.997 | PEG6 | |||
3.045 | 2.015 | 171.899 | 0.083 | 171.982 | PEG7 | |||
2.312 | 3.815 | 0.77 | 171.129 | 0.0415*3= 0.1245 | 171.2535 | CP2 | ||
1.743 | 3.227 | 0.915 | 170.214 | 0.0415*4=0.166 | 170.38 | CP3 | ||
2.735 | 0.992 | 169.222 | 0.166 | 169.388 | PEG10 | |||
3.623 | 0.888 | 168.334 | 0.166 | 168.5 | TBM 2 | |||
6.714 | 13.88 | 2.87 | 10.036 |