In: Civil Engineering
A truck will haul an average load of 15 cy, heaped capacity, and loose measure per load. Use average values of swell factors in Table 7.3 on p. 131 of your textbook to determine the volume of the truck in bank measure when the material is sand, ordinary earth, dense clay, and well-blasted rock.
Then, using an Excel spreadsheet, determine the number of trucks required to move material in the following scenario:
A project requires 40,000 cy of compacted fill that must be completed in 32 working days. The fill material will be hauled to the site in 21 cy loose measure trucks. The cycle time for a truck is 40 min. per trip. The swell factor for the earth is 25% and the shrinkage factor is 10%. Assume 8 hours per day and a 45-min. effective hour. Determine the number of required trucks to complete the project in 32 days.
Deliverable:
Upon completion of this project, you will deliver an excel
spreadsheet to include:
Given data: | |||||
Haul an average load of Track = L = | 15 | cy | |||
Sand, Sw = 10% − 15%: | |||||
Assume Avg. swell factor = Sw = | 12% | ||||
Volume in truck, B = L / (1 + Sw) | |||||
B= | 13.39 | cy | |||
Ordinary earth, Sw = 20% − 30%: | |||||
Assume Avg. swell factor = Sw = | 25% | ||||
Volume in truck, B = L / (1 + Sw) | |||||
B= | 12.0 | cy | |||
Dense clay, Sw = 25% − 40%: | |||||
Assume Avg. swell factor = Sw = | 35% | ||||
Volume in truck, B = L / (1 + Sw) | |||||
B= | 11.1 | cy | |||
Well-blasted rock, Sw = 50% − 80%: | |||||
Assume Avg. swell factor = Sw = | 55% | ||||
Volume in truck, B = L / (1 + Sw) | |||||
B= | 9.7 | cy |
Required production ratefor compacted measure | ||||||
Given, | ||||||
Volume for compacted measure = L1 = | 40000 | cy | ||||
Completion time = T = | 32 | days | ||||
Production rate = L1 / T = | 1250 | cy/day | ||||
Production rate of one truck: | ||||||
Given, | ||||||
Swell factor for the earth = Sw = | 25% | |||||
Loose measure payload in truck, L2 = | 21 | cy | ||||
Bank measure payload in truck, B = L2/ (1 + Sw) | ||||||
B= | 16.8 | cy | ||||
Shrinkage factor = | 10% | |||||
Compacted measure payload in truck, C = (1 − Sh) B | ||||||
C= | 15.12 | cy/day | ||||
The cycle time for a truck is = T = | 40 | min. per trip. | ||||
8 | hours per day and a | 45 | min. effective hour. | |||
Total effective hour = te = | 6 | hour / day | ||||
Daily production rate = P = (C/T)x te x 60 min. / hour | ||||||
for compacted measure | P = | 136.08 | cy/day, | |||
Number of required trucks: | ||||||
Required trucks = (Required production rate) / (production rate of one truck) | ||||||
Required trucks = | P/C | |||||
= | 9 | tracks | ||||
Given data: Haul an average load of Track = L = 15 cy Sand, Sw = 10% − 15%: Assume swell factor = 12% Volume in truck, B = L / (1 + Sw) B= 13.39 cy Ordinary earth, Sw = 20% − 30%: Assume swell factor = 25% Volume in truck, B = L / (1 + Sw) B= 12.0 cy Dense clay, Sw = 25% − 40%: Assume swell factor = 35% Volume in truck, B = L / (1 + Sw) B= 11.1 cy Well-blasted rock, Sw = 50% − 80%: Assume swell factor = 55% Volume in truck, B = L / (1 + Sw) B= 9.7 cy Required production ratefor compacted measure Given, Volume for compacted measure = L1 = 40000 cy Completion time = T = 32 days Production rate = L1 / T = 1250 cy/day Production rate of one truck: Given, Swell factor for the earth = Sw = 25% Loose measure payload in truck, L2 = 21 cy Bank measure payload in truck, B = L2/ (1 + Sw) B= 16.8 cy shrinkage factor = 10% Compacted measure payload in truck, C = (1 − Sh) B C= 15.12 cy/day The cycle time for a truck is = T = 40 min. per trip. 8 hours per day and a 45 min. effective hour. Total effective hour = te = 6 hour / day Daily production rate = P = (C/T)x te x 60 min. / hour for compacted measure P = 136.08 cy/day, Number of required trucks: Required trucks = (Required production rate) / (production rate of one truck) Required trucks = P/C = 9 tracks