Question

In: Statistics and Probability

The National Association of Truck Drivers claims that the average truck driver travels 60000 miles per...

The National Association of Truck Drivers claims that the average truck driver travels 60000 miles per year. The population standard deviation of the mileage is 5000 miles. The Connecticut Valley Trucking Corporation surveyed 48 Truck Drivers and found the mean mileage for its Truck Drivers was 59500 miles driven per year. Is Connecticut Valley’s mileage different from that claimed by the National Association of Truck Drivers at the .05 significance level?

Solutions

Expert Solution

Solution :

Given that ,

= 60000

= 59500

= 5000

n = 48

The null and alternative hypothesis is ,

H₀ : = 60000

H_a : 60000

This is the two tailed test .

Test statistic = z

= ( - ) / / n

= ( 59500 - 60000) / 5000 / 48

= -0.69

The test statistic = -0.69

P - value = 2 * P (Z < -0.69 )

= 2 * 0.2451

= 0.4902

P-value = 0.4902

= 0.05

0.4902 > 0.05

P-value >

Fail to reject the null hypothesis .

There is not sufficient evidence to test the claim .

orchestra answered 1 year ago

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