Solve the following equations: 3cos(x)+1=cos(x)3cos⁡(x)+1=cos⁡(x), where x is in the interval [0,2π)[0,2π) x=? sin(2x)=−12sin⁡(2x)=−12, where x...

Solve the following equations:

3cos(x)+1=cos(x)3cos⁡(x)+1=cos⁡(x), where x is in the interval [0,2π)[0,2π)
x=?
sin(2x)=−12sin⁡(2x)=−12, where x is in the interval [0,2π)[0,2π).
x=?

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Expert Solution

milcah answered 1 year ago

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