Question

QUESTİON 2-HOMEWORK1 QUESTİON
experienced and beginner officers at a police station.While preparing the guard of roster,
Two-person patrols consisting of an experienced and a beginner will be identified.Every experienced officer must keep watch with all beginner officers.
the number of officers entered on the keyboard (up to 30) and according to the registration numbers of the officers.

Write the c ++ program, which writes the registration numbers and patrol guard lists of the beginner and experienced officers, in accordance with the prototype given in the options.
NOTE:
The registration numbers of experienced officers are odd and the registration numbers of novice officers are double.
It is assumed that at least one experienced and a beginner registration number will be entered from the keyboard.
EXAMPLE:
enter the number of officers:6
Enter the registration numbers of 6 officers:
18 25 28 13 296 160

registration numbers of beginner officers:18, 28,296,160

registration numbers of experienced officers:25,13
watch list:
25-18
25-28
25-296
25-160
13-18
13-28
13-296
13-160

QUESTİON2 You see the prototype at the bottom in the order of the function.
List of registration numbers sent from the main functions and in the main function takes the number of officers entered from the keyboard as parameters
Prints the above screen output in the function.

void deneyimliAcemiAyirarakYaz(int sicil[],int memurSayisi);

HOMEWORK1 you saw the prototype at the bottom List of registration number sent from the main
in order of function,officer count,experienced and beginner worker gets the empty list.

void deneyimliAcemiAyir(int *,int memurSayisi,int *,int *);

function fills empty lists.Results must be printed in the main function.

.

Answer 1

//Required c++ program for first question:

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int n,x;
    cout<<"Enter the number of officers: ";
    cin>>n;
    cout<<"Enter the regustration numbers of "<<n<<" officers: ";
  
    vector<int>exp,beg; //creating vectors for both type of officers
  
    for(int i=0;i<n;i++){
      
        cin>>x; //taking input reg. no.
      
        if(x%2==0){ //if even pushing in beg vector
          
            beg.push_back(x);
          
        } else { //if odd pushing in exp vector
          
            exp.push_back(x);
          
        }
    }
  
    //Printing the two lists
    cout<<"Registration numbers of beginner officers: ";
    for(int i=0;i<beg.size();i++){
        cout<<beg[i]<<" ";
    }
    cout<<endl;
  
    cout<<"Registration numbers of experienced officers: ";
    for(int i=0;i<exp.size();i++){
        cout<<exp[i]<<" ";
    }
    cout<<endl;
  
    cout<<"Watch List:"<<endl; //printing watch list
  
    for(int i=0;i<exp.size();i++){ //looping in experienced officers
      
        for(int j=0;j<beg.size();j++){ //looping in beginner officers
          
            cout<<exp[i]<<"-"<<beg[j]<<endl;
        }
    }
  
    return 0;
}

Please refer to the screenshot of the code to understand the indentation of the code

Sample Run:

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