In: Statistics and Probability
|
N =16 G = 120 ΣX² = 1036 |
The following scores are from an independent-measure study comparing two treatment conditions.
|
Treatment |
|
|
I |
II |
|
10 |
7 |
|
8 |
4 |
|
7 |
9 |
|
9 |
3 |
|
13 |
7 |
|
7 |
6 |
|
6 |
10 |
|
12 |
2 |
First we need t find the mean and SD of both treatments. Following table shows the calculations:
| Treatment 1, X1 | (X1-mean)^2 | Treatment 2, X2 | (X2-mean)^2 | |
| 10 | 1 | 7 | 1 | |
| 8 | 1 | 4 | 4 | |
| 7 | 4 | 9 | 9 | |
| 9 | 0 | 3 | 9 | |
| 13 | 16 | 7 | 1 | |
| 7 | 4 | 6 | 0 | |
| 6 | 9 | 10 | 16 | |
| 12 | 9 | 2 | 16 | |
| Total | 72 | 44 | 48 | 56 |
Sample size

Mean:

Standard deviation:


(a)

Conclusion: We can conclude that at 5% level of significance,there is a significant mean difference between the two treatments.
(b)
First be need to find grand mean so

Let
shows
the mean of the ith group. So


and

Therefore

----
Since there are 2 different groups so we have k=2. Therefore degree of freedoms are:



-------------
Now


F test statistics is

The p-value is 0.0414.
Since p-value is less than 0.05 so we reject the null hypothesis.
Conclusion: We can conclude that at 5% level of significance,there is a significant mean difference between the two treatments.