In: Other
Learning curve \(=80 \%\)
Time for first transplant \(=27\) hours
From Learning-Curve Coefficient Approach we know
\(T_{N}=T_{1} C\)
\(T_{N}=\) number of hours required to transplant the Nth unit
\(\mathrm{T}_{1}=\) number of hours required to transplant the 1st unit
\(C=\) learning-curve coefficient \(=\mathrm{N}^{\text {(log of learning rate } / \text { log2) }}\)
a)
By using the table E.3 for 10th transplant with 80\%learning curve \(C=0.477\)
Time to complete 10th transplant \(T_{10}=27^{*} 0.477=12.879\) hours
b) cost of 10 th surgery \(=\) No of hours to complete 10 th transplant * cost per hour \(=12.879 * 5200=\) \(\$ 66970.8\)
c) To complete total 10 transplants with learning curve \(80 \% \mathrm{C}=6.315\)
Total time for first 10 transplants \(=27^{*} 6.315=170.505\)
d) Total cost for 10 surgeries \(=170.505^{*} 5200=\$ 886626\)