In: Statistics and Probability
Calculate an 80% CI for mean US population height (in inches),using your heights.Heights of individuals in US is normally distributed.
Heights are 6ft 1, 5 ft 2, and 5 ft 5
Solution:
We have to find 80% CI for mean US population height (in inches).
Heights of individuals in US is normally distributed.
Heights are 6ft 1, 5 ft 2, and 5 ft 5
First we need to convert these heights in inches,
1 foot = 12 inches
thus we get:
Height in foot | Calculations | Height in inches |
---|---|---|
6ft 1 | =6x12 + 1 = | 73 |
5ft 2 | =5x12 + 2 = | 62 |
5ft 5 | =5x12 + 5 = | 65 |
Formula:
where
Thus we need to make following table:
x: Height in inches | x^2 |
---|---|
73 | 5329 |
62 | 3844 |
65 | 4225 |
Thus we get:
and
tc is t critical value for c = 80% confidence level
df = n - 1= 3 - 1 = 2
two tail area = 1 - 0.80 = 0.20
tc = 1.886
Thus
Thus 80% confidence interval is:
Thus 80% CI for mean US population height (in inches) , is .