In: Statistics and Probability
Student NOVA 5 c311
1 139 137
2 142 144
3 141 137
4 139 139
5 144 139
6 147 143
7 143 136
8 144 139
9 145 140
10 138 138
11 141 139
12 141 137
13 145 144
14 142 140
15 142 138
16 138 135
Is there a statistically significant difference in results between the NOVA 5 method and the c311 method?
What is the basis for your answer?
H0:Null Hypothesis:
HA:Alternative Hypothesis:
From the given data, the following statistics are calculated:
n1 = 16
1 = 141.94
s1=2.6458
n2 = 16
2 = 139.06
s2 = 2.6702
Test statistic is:
t = (141.94 - 139.06)/0.9397 = 3.06
= 0.05
ndf = n1+n2 - 2= 16 + 16- 2 = 30
From Table, critical values of t = 2.0423
Since the calculated value of t = 3.06 is greater than critical value of t = 2.0423, the difference is significant. Reject null hypothesis.
Conclusion:
The data support the claim that there is a statistically
significant difference in results between the NOVA 5 method and the
c311 method.
The basis of our answer is that the populations of NOVA 5 method and the c311 method are normal distributions.