Question

Determine the solubility of silver chloride in 0.10 M sodium chloride solution. The Ksp for silver chloride is 1.1 x 10-10.

Answer 1

The solubility equation of AgCl can be written as

Hence, the expression of equilibrium constant K_sp can be written as

Note that we have a solution of sodium chloride with concentration 0.10 M.

Since NaCl is a strong electrolyte, it dissociates completely to give the following concentrations of its ions.

Now, note that Cl^- is a common ion between NaCl and AgCl. Since the dissociation of AgCl produces a small amount of Cl^- ,  we can assume the equilibrium concentration of Cl^- to be 0.10 M.

Hence, we can write

Hence, of AgCl can be dissolved in order to produce concentration of Ag⁺ ions.

Hence, the molar solubility of silver chloride is in the given solution.

Note: the solubility can be expressed in g/L as follows:

Molar mass of AgCl = 143.32 g/mol

Hence, the mass of AgCl that can dissolve in 1 L is

Hence, the solubility in g/L for AgCl is approximately in the given solution.