(3 pts) Solve the initial value problem
25y′′−20y′+4y=0, y(5)=0, y′(5)=−e2.
(3 pts) Solve the initial value problem
y′′ − 2√2y′ + 2y = 0, y(√2) = e2, y′(√2) = 2√2e2.
Consider the second order linear equation t2y′′+2ty′−2y=0,
t>0.
(a) (1 pt) Show that y1(t) = t−2 is a solution.
(b) (3 pt) Use the variation of parameters method to obtain a
second solution and a general solution.
Solve the following initial value problem over the interval from
t = 0 to 2 where y(0) = 1 using the following
methods.
dy/dt=y*t^2−1.1y
a) Analytical method
b) Euler's method with h=0.5 at t=2
c) Euler's method with h=0.25 at t=2
d) Midpoint method with h=0.5 at t=2
e) Fourth-order Runge-Kutta method with h=0.5 at t=2
f) Display all yor results obtained above on the same graph
Solve the following initial value problem over the interval from
t = 0 to 1 where y(0) = 1 using the following
methods with a step size of 0.25.
dy/dt=(1+4t)*sqrt(y)
a) Analytical method
b) Euler's method
c) Heun's method without iteration
d) Ralston's method
e) Fourth-order Runge-Kutta method
f) Display all your results obtained above on the same graph
1. Use the Laplace transform to solve the initial value
problem.
?"+4?′+3?=1−?(?−2)−?(?−4)+?(?−6), ?(0)=0, ?′(0)=0
2. Use the Laplace transform to solve the initial value
problem.
?"+4?=?(?), ?(0)=1, ?′(0)=−1
= { 1, ? < 1
where ?(?) = {0, ? > 1.
Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1,
y'(0) = 0.
Solve without the Laplace Transform, first, and then with the
Laplace Transform.