Question

In: Advanced Math

(Investment): An investor has $150,000 to invest in oil stock, steel stock, and government bonds. The...

(Investment): An investor has $150,000 to invest in oil stock, steel stock, and government bonds. The bonds are guaranteed to yield 5%, but the yield for each stock can vary. To protect against major losses, the investor decides that the amount invested in oil stock should not exceed $50,000. The total amount invested in stock CANNOT exceed the amount invested in bonds by more than $25,000.

a) Set up the problem (decision variables, problem constraints, non-negativity constraints).

b) Now form the objective function if oil stock yields 12% and the steel stock yields 9%. How much should be invested in each alternative in order to maximize the return (don't forget the bonds). What is the maximum return?

Solutions

Expert Solution

x1 = amount invest in oil stock

x2 = amount invest in steel stock

x3 = amount invest in government bonds

.

.....................An investor has $150,000 to invest

.

...................the amount invested in oil stock should not exceed $50,000

.

..............The total amount invested in stock CANNOT exceed the amount invested in bonds by more than $25,000.

.

our system is

subject to

.

After introducing slack variables

subject to

.

Iteration-1 Cj 0.12 0.09 0.05 0 0 0
B CB XB x1 x2 x3 S1 S2 S3 MinRatio
XB/x1
S1 0 150000 1 1 1 1 0 0 150000/1=150000
S2 0 50000 1 0 0 0 1 0 50000/1=50000
S3 0 25000 (1) 1 -1 0 0 1 25000/1=25000
Z=0 Zj 0 0 0 0 0 0
Zj-Cj -0.12↑ -0.09 -0.05 0 0 0



Negative minimum Zj-Cj is -0.12 and its column index is 1.

Minimum ratio is 25000 and its row index is 3.

The pivot element is 1.

Entering x1, Departing S3

.


Cj 0.12 0.09 0.05 0 0 0
B CB XB x1 x2 x3 S1 S2 S3 MinRatio
XB/x3
S1 0 125000 0 0 2 1 0 -1 125000/2=62500
S2 0 25000 0 -1 (1) 0 1 -1 25000/1=25000
x1 0.12 25000 1 1 -1 0 0 1 ---
Z=3000 Zj 0.12 0.12 -0.12 0 0 0.12
Zj-Cj 0 0.03 -0.17↑ 0 0 0.12


Negative minimum Zj-Cj is -0.17 and its column index is 3.

Minimum ratio is 25000 and its row index is 2.

The pivot element is 1.

Entering =x3, Departing =S2,

.


Iteration-3 Cj 0.12 0.09 0.05 0 0 0
B CB XB x1 x2 x3 S1 S2 S3 MinRatio
XB/x2
S1 0 75000 0 (2) 0 1 -2 1 75000/2=37500
x3 0.05 25000 0 -1 1 0 1 -1 ---
x1 0.12 50000 1 0 0 0 1 0 ---
Z=7250 Zj 0.12 -0.05 0.05 0 0.17 -0.05
Zj-Cj 0 -0.14↑ 0 0 0.17 -0.05



Negative minimum Zj-Cj is -0.14 and its column index is 2.

Minimum ratio is 37500 and its row index is 1.

The pivot element is 2.

Entering =x2, Departing =S1,
.

Iteration-4 Cj 0.12 0.09 0.05 0 0 0
B CB XB x1 x2 x3 S1 S2 S3 MinRatio
x2 0.09 37500 0 1 0 0.5 -1 0.5
x3 0.05 62500 0 0 1 0.5 0 -0.5
x1 0.12 50000 1 0 0 0 1 0
Z=12500 Zj 0.12 0.09 0.05 0.07 0.03 0.02
Zj-Cj 0 0 0 0.07 0.03 0.02



Since all  

Hence, optimal solution is arrived

50000 = invest in oil stock

37500= invest in steel stock

62500 = invest in government bonds

.

maximum return is 12500


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